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enyata [817]
3 years ago
13

The function h(t = 200 – 16t2 represents the height of a ball dropped from 200 feet. how far had the ball traveled after falling

for 11 seconds?
a. 16 feet
b. 24 feet
c. 176 feet
d. 200 feet
Mathematics
1 answer:
Serga [27]3 years ago
5 0
The answer to your question is c

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The length of a swimming pool is 3 feet longer than it’s width. The swimming pool is surrounded by a deck that is 2 feet wide an
Firlakuza [10]

Answer:

The Length of swimming pool is 8.35 feet

The width of swimming pool is 5.35 feet

Step-by-step explanation:

Given as :

The length of swimming pool is 3 feet longer that its width

Let The width of swimming pool = w  feet

So, The Length of swimming pool = L = (w + 3) feet

Now, The swimming pool is surrounded by deck of 2 feet wide

The width of deck = w' = w + 2 + 2 = (w + 4) feet

The area of deck = 116 feet²

The length of deck = L' = L + 2 + 2 = (L + 4) feet

So, L' = (w + 3 + 4) feet

I.e L' = (w + 7) feet

∵ The area of deck = 116 feet²

So , L' × w' = 116 feet²

(w + 7)× (w + 4) = 116

Or, w² + 4 w + 7 w + 28 = 116

Or, w² + 11 w - 88 = 0

Solving the quadratic equation as

ax² + bx + c = 0

So, w = \dfrac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

Or, w = \dfrac{-11\pm \sqrt{11^{2}-4\times 1\times (-88)}}{2\times 1}

Or, w = \dfrac{-11\pm \sqrt{473}}{2}

or, w = \dfrac{-11\pm 21.7}{2}

or, w = 5.35 , -16.35

The width of swimming pool = w = 5.35 feet

The Length of swimming pool = L = (5.35 + 3) feet = 8.35 feet

Hence, The Length of swimming pool is 8.35 feet

And The width of swimming pool is 5.35 feet

Answer

3 0
3 years ago
The transformation of 'f' is represented by 'g'. Write a rule for g. f(x)=\root(3)(x). Then show your check steps.
podryga [215]

Answer:

g(x)=-2\sqrt[3]x

or

g(x) = -2f(x)

Step-by-step explanation:

Given

f(x) = \sqrt[3]x

Required

Write a rule for g(x)

See attachment for grid

From the attachment, we have:

(x_1,y_1) = (-1,2)

(x_2,y_2) = (1,-2)

We can represent g(x) as:

g(x) = n * f(x)

So, we have:

g(x) = n * \sqrt[3]x

For:

(x_1,y_1) = (-1,2)

2 = n * \sqrt[3]{-1}

This gives:

2 = n * -1

Solve for n

n = \frac{2}{-1}

n = -2

To confirm this value of n, we make use of:

(x_2,y_2) = (1,-2)

So, we have:

-2 = n * \sqrt[3]1

This gives:

-2 = n * 1

Solve for n

n = \frac{-2}{1}

n = -2

Hence:

g(x) = n * \sqrt[3]x

g(x)=-2\sqrt[3]x

or:

g(x) = -2f(x)

4 0
3 years ago
The equation of a circle in general form is ​ x2+y2+20x+12y+15=0 ​ . What is the equation of the circle in standard form?
mestny [16]

Answer:

(x)²+(y)²=0

Step-by-step explanation:

6 0
3 years ago
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Joey is staking out a spot for a rectangular pen he is building for his new pig. He has three stakes already plotted on the coor
andreev551 [17]

Answer:2-6

Step-by-step explanation:

36

6 0
3 years ago
Read 2 more answers
Make g the subject of this relation​
zhannawk [14.2K]

Answer:

see explanation

Step-by-step explanation:

Simplify the radical

\frac{U}{\frac{1}{f}+\frac{1}{g}  }

= \frac{U}{\frac{g+f}{fg} }

= \frac{Ufg}{g+f}

Square both sides

T² = \frac{Ufg}{g+f} ( multiply both sides by (g + f) )

T²(g + f) = Ufg ( distribute left side )

T²g + T²f = Ufg ← subtract Ufg from both sides

T²g - Ufg + T²f = 0 ← subtract T²f from both sides

T²g - Ufg = - T²f ← factor out g from each term on the left side

g(T² - Uf) = - T²f ← divide both sides by (T² - Uf)

g = - \frac{T^2f}{T^2-Uf} = \frac{T^2f}{Uf-T^2}

6 0
3 years ago
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