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bekas [8.4K]
3 years ago
8

1: Distance: 238 miles

Mathematics
1 answer:
wlad13 [49]3 years ago
5 0

Answer:

  1. 42.5 mph
  2. 25 5/89 mph
  3. 30 mph

Step-by-step explanation:

speed = distance / time

1. (238 mi)/(5.6 h) = 42.5 mph

2. (446 mi)/(17.8 h) = 25.0561... mph . . . (a very long repeating decimal)

3. (387 mi)/(12.9 h) = 30 mph

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Becky took a quiz in science today. She answered 16 out of 25 correct. What is her score?
Slav-nsk [51]
If you want to know her percentage, we do:
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Her score is 64%
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4 years ago
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The 373 students who listed soccer as their favorite sport were 13 more than three times the number of students who listed baske
wariber [46]
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Will give crown will post more
marta [7]

Answer:

2, 7, 27, 42

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Use Theorem 2.1.1 to verify the logical equivalence. Give a reason for each step. -(pv –q) v(-p^q) = ~p
sertanlavr [38]

Answer:

The statement \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) is equivalent to \lnot p, \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv \lnot p

Step-by-step explanation:

We need to prove that the following statement \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) is equivalent to \lnot p with the use of Theorem 2.1.1.

So

\lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv

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\equiv (\lnot p \land q)\lor(\lnot p \land \lnot q) by the Double negative law

\equiv \lnot p \land (q \lor \lnot q) by the Distributive law

\equiv \lnot p \land t by the Negation law

\equiv \lnot p by Universal bound law

Therefore \lnot(p\lor\lnot q)\lor(\lnot p \land \lnot q) \equiv \lnot p

4 0
3 years ago
Does anyone know this?
Verdich [7]
S=2 \pi r 

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4 years ago
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