Question

Let f(x) = x2 + 6 and g(x) = x + 8x g ( x ) = x + 8/ x . Find ( g o f)(­ -7)

Answer 1

Answer:

63/55

Step-by-step explanation:

Assuming $f(x) = x^2+6$ and $g(x) = x + {8}{x}$. Find  ( g o f)(­ -7) by substituting f into g. Then -7 into the new expression.

( g o f)(­ -7) =

$\frac{(x^2+6) +8}{x^2+6} \\\\ \frac{((-7)^2+6) + 8}{(-7)^2+6} \\\\ \frac{49+6+8}{49+6}\\\\ \frac{55 + 8}{55} \\\\\frac{63}{55}$