Answer:
$1,313.3 per month
Step-by-step explanation:
A=p(1+r/n)^nt
P=principal=$75,000
r=interest rate=7.2%=0.072
t=20 years
n=12 months
A=p(1+r/n)^nt
=75,000(1+0.072/12)^12*20
=75,000(1+0.006)^240
=75,000(1.006)^240
=75,000(4.2026)
=315,195
A=$315,195
The term of Lauren's loan=20 years
20 years×12 months=240 months
Lauren's pay per month =$315,195/240
=$1,313.3125
Approximately $1,313.3 per month
Answer:
4.5 cups
Step-by-step explanation:
The shape of the graph is very similar to a natural logarithm, which is ln(x). ln(x) has an asymptote at x=0. Shift the graph 3 units to the left and you have the graph of ln(x+3), which has an asymptote at x= -3. Also, when x=0, ln(x+3) is about 1. I think ln(x+3) is the answer. Check this online graph to see if this matches:
https://www.desmos.com/calculator/ac1axswddl
Have a nice day!
11) 2x+6y-3; x=5,y=4
the question is asking to evaluate for y when x=5 and evaluate for x when y=4,
2x+6y-3
2x+6y=3
2(5)+6y=3
10+6y=3
6y=3-10
y=-7/6 when x=5
2x+6(4)=3
2x+24=3
2x=3-24
x=-21/2 when y=4
12)
Input Output
N 4(n+3)
12 4(12+3) = 4(15)=60
14 4(14+3)=4(17)=68
18 4(18+3)=4(21)=84
25 4(25+3)=4(28)=112
13)8x+y-10; x=4, y=50
8x+y=10
8(4)+y=10
32+y=10
y=10-32
y=-22 when x=4
8x+50=10
8x=10-50
8x=-40
x=-40/8
×=-5/1=-5 when y=50
14) b is correct
15)c is correct
16) c is correct
If you need explanations on these questions, message me.
<h3>All options satisfies the given inequality</h3>
<em><u>Solution:</u></em>
Given that,
![y < | 3x | + 1](https://tex.z-dn.net/?f=y%20%3C%20%7C%203x%20%7C%20%2B%201)
Here, modulus means that, the absolute value of a number is never negative
<em><u>Option A</u></em>
![(2, -9)](https://tex.z-dn.net/?f=%282%2C%20-9%29)
Substitute x = 2 and y = -9 in given
![-9 < | 3(2)| + 1\\\\-9 < 6 + 1\\\\-9 < 7](https://tex.z-dn.net/?f=-9%20%3C%20%7C%203%282%29%7C%20%2B%201%5C%5C%5C%5C-9%20%3C%206%20%2B%201%5C%5C%5C%5C-9%20%3C%207)
-9 is less than 7 is true
This forms a solution to given inequality
<em><u>Option B</u></em>
(-4, 12)
Substitute x = -4 and y = 12 in given
![12 < | 3(12)| + 1\\\\12 < 36 + 1\\\\\12 < 37](https://tex.z-dn.net/?f=12%20%3C%20%7C%203%2812%29%7C%20%2B%201%5C%5C%5C%5C12%20%3C%2036%20%2B%201%5C%5C%5C%5C%5C12%20%3C%2037)
12 is less than 37 is true
This forms a solution to given inequality
<em><u>Option C</u></em>
(3, 15)
Substitute x = 3 and y = 15 in given
![15 < | 3(15)| + 1\\\\15 < 45+1\\\\15< 46](https://tex.z-dn.net/?f=15%20%3C%20%7C%203%2815%29%7C%20%2B%201%5C%5C%5C%5C15%20%3C%2045%2B1%5C%5C%5C%5C15%3C%2046)
15 less than 46 is true
This forms a solution to given inequality
<em><u>Option D</u></em>
(0, 0)
Substitute x = 0 and y = 0 in given
![0 < | 3(0) | + 1\\\\0 < 0 + 1\\\\0 < 1](https://tex.z-dn.net/?f=0%20%3C%20%7C%203%280%29%20%7C%20%2B%201%5C%5C%5C%5C0%20%3C%200%20%2B%201%5C%5C%5C%5C0%20%3C%201)
0 is less than 1
This forms a solution to given inequality