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3 years ago

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

2 answers:

4 0

5/6a - 5/6b + 1/3a

1/3 x 2/2 = 2/6

5/6a + 2/6a = 7/6a

7/6a - 5/6a = 2/6a

2/6a = 1/3a

d. 1/3a is your answer

hope this helps

Kamila [148]3 years ago

3 0

A. 7/6a - 5/6b would be the answer
add all like terms = 5/6 + 2/6 (Change 1/3 to 2/6 so the denominators are the same) which is 7/6.
You cannot add 5/6b and 7/6a because they are not like terms.
Your final answer would be 7/6a - 5/6b
Hope this helps!!

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<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B3%7D%20k%20-%20%28k%20%2B%20%20%5Cfrac%7B1%7D%7B4%7D%29%20%3D%20%20%5Cfrac

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Firstly, foil -(k + 1/4) (think of the minus sign as -1):

$\frac{2}{3}k-k-\frac{1}{4}=\frac{1}{12}k+\frac{4}{12}$

Next, combine like terms:

$-\frac{1}{3}k-\frac{1}{4}=\frac{1}{12}k+\frac{4}{12}$

Next, we have to add 1/3k on both sides, but first we have to find the LCD, or lowest common denominator, of 3 and 12. To do this, list the multiples of both and the lowest one they share is their LCD. In this case, the LCD is 12. Multiply both sides of -1/3 by 4/4 and 1/12 by 1/1:

$-\frac{1}{3}\times \frac{4}{4}=-\frac{4}{12}\\\\\frac{1}{12}\times \frac{1}{1}=\frac{1}{12}\\\\-\frac{4}{12}k-\frac{1}{4}=\frac{1}{12}k+\frac{4}{12}$

Now add 4/12k on both sides of the equation:

$-\frac{1}{4}=\frac{5}{12}k+\frac{4}{12}$

Next, to subtract 4/12 on both sides we need to find the LCD of 4 and 12. It's the similar process as we did with 12 and 3. This time the LCD is also 12. Multiply both sides of -1/4 by 3/3 and 4/12 by 1/1:

$-\frac{1}{4}\times \frac{3}{3}=-\frac{3}{12}\\\\\frac{4}{12}\times \frac{1}{1}=\frac{4}{12}\\\\-\frac{3}{12}=\frac{5}{12}k+\frac{4}{12}$

Now subtract 4/12 on both sides:

$-\frac{7}{12}=\frac{5}{12}k$

Lastly, multiply both sides by 12/5, and your answer will be:

$-\frac{84}{60}=-\frac{7}{5}=k$

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