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kiruha [24]
2 years ago
5

Idk how to do this . help me fr‍♀️

Mathematics
1 answer:
lana [24]2 years ago
3 0

sqrt(29) = 5.385

This means it is inbetween 5 and 6.

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Solve for aaa: a-\left(-3.75\right)=6.11a−(−3.75)=6.11a, minus, left parenthesis, minus, 3, point, 75, right parenthesis, equals
Ganezh [65]

Answer:

Step-by-step explanation:

                              To isolate <em>a</em>, we add -3.75 to both sides.

                                              <em>a</em>-(-3.75)=6.11

                                   <em>a</em>-(-3.75)<u><em>+(-3.75)</em></u>=6.11<u><em>+(-3.75)</em></u>

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3 years ago
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Answer:

Range=14

\sigma^2 =32.4

\sigma = 5 .7

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

Data: 136, 129, 141, 139, 138, 127

Solving (a): The range

This is calculated as:

Range = Highest - Least

Where:

Highest = 141; Least = 127

So:

Range=141-127

Range=14

Solving (b): The variance

First, we calculate the mean

\bar x = \frac{1}{n} \sum x

\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)

\bar x = \frac{1}{6} *810

\bar x = 135

The variance is calculated as:

\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2

So, we have:

\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]

\sigma^2 =\frac{1}{5}*[162]

\sigma^2 =32.4

Solving (c): The standard deviation

This is calculated as:

\sigma = \sqrt {\sigma^2 }

\sigma = \sqrt {32.4}

\sigma = 5 .7 --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

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2 years ago
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