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anzhelika [568]
3 years ago
6

5) James and Andrew are considering adding some premium channels to their satellite package. The cost of

Mathematics
1 answer:
liberstina [14]3 years ago
5 0

Answer:

Part (A): The slope is 7.

Part (B): The required equation of line is y=7x+38.6.

Part (C): The base price is $38.6

Step-by-step explanation:

Consider the provided information.

The cost of  their total bill if they added 1 and 4 premium channels is $45.60 and $66.60, respectively.

For 1 premium channel they need to pay $45.60.

This can be written as: (1, 45.60)

For 4 premium channel they need to pay $66.60.

This can be written as: (4, 66.60)

Part (A) Find the slope.

Slope=m=\frac{y_2-y_1}{x_2-x_1}

Substitute (x_1,y_1)=(1, 45.60) and (x_2,y_2)=(4, 66.60) in above formula.

m=\frac{66.60-45.60}{4-1}

m=\frac{21}{3}=7

Hence, the slope is 7.

Part (B) Write the equation of the line.

By using one of the point and slope we can write the equation of line.

Point slope formula: (y-y_1)=m(x-x_1)

Substitute the respective values in the above formula.

(y-45.60)=7(x-1)

y-45.60=7x-7

y=7x+38.6

Hence, the required equation of line is y=7x+38.6.

Part (C) Determine the base price (with O premium channels)

Substitute x=0 in y=7x+38.6.

y=7(0)+38.6

y=38.6

Hence, the base price is $38.6

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1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt
Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]

Given that

\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]

Let:

<em />L \to<em> Letters</em>

<em />C \to<em> Cost</em>

<em />

Using proportional reasoning, we have:

C  = kL

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<em />k \to<em> ratio of proportion</em>

For the first values of C and L, we have:

C  = kL

0.45 = k \times 10

Divide both sides by 10

k = 0.045

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C = 0.045L

<u>When C = 6.75, we have:</u>

C = 0.045L

6.75 = 0.045L

Solve for L

L = \frac{6.75}{0.045}

L = 150

<u>When L = 7, we have:</u>

C = 0.045L

C = 0.045 \times 7

C = 0.315

<u>When L = 1, we have:</u>

C = 0.045L

C = 0.045 \times 1

C = 0.045

<u>When L = 500, we have:</u>

C =0.045L\\

C =0.045 \times 500

C =22.5

<u>When C = 18.90, we have:</u>

C = 0.045L

18.90 = 0.045L

Solve for L

L=\frac{18.90}{0.045}

L=420

Hence, the complete table is:

\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]

Read more about proportions at:

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Answer with Step-by-step explanation:

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