Answer:
Given the equation: 
rewrite the above equation as: 
Like terms are those whose variables are same.
Combine like terms :
....[1]
Now, to solve the above quadratic equation:
For quadratic equation:
where a,b, and c are constant.
then the solutions are:
...[2]
in equation [1], the values of a= 4, b=-10 and c= -24.
then, by putting these in the [2] we get,

On solving we get, the solutions are:
and 
Check :
By substituting the values of x= -1.5 and x=4 in equation
we have;
for x=-1.5



9+10.5=19.5
19.5=19.
Similarly, for x=4



64-28=36
36=36
Therefore, the only solution of the equation
is, x= -1.5 and x=4