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liq [111]
3 years ago
10

Write the absolute value equations in the form x−b =c (where b is a number and c can be either number or an expression) that hav

e the following solution sets: Two solutions: x=−2, x=−32.
Mathematics
1 answer:
Anastaziya [24]3 years ago
7 0

Answer:

  |x +17| = 15

Step-by-step explanation:

The absolute value equation ...

  |x -b| = c

can be rewritten as two equations:

  x -b = -c

  x -b = c

The solution to the first is x = b -c.

The solution to the second is x = b +c.

__

The first solution is the smaller of the two, so we have ...

  b -c = -32

  b +c = -2

Adding these two equations gives ...

  2b = -34   ⇒   b = -17

Subtracting the first equation from the second gives ...

  2c = 30   ⇒   c = 15

The the equation you seek is ...

  |x +17| = 15

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MatroZZZ [7]

Applying parallel line postulate twice

36degree=3x degree +2y degree

126 degrees=12 x degree + 2y degree

So, the two equations are:

3x + 2y = 36

and

12x + 2y = 126

Eliminate x to solve for y

-(3x + 2y)= -(36)

-3x - 2y = -36

Combine the equations

(-3x - 2y)+ (12x + 2y) = (-36) + (126)

-3x -2y + 12x + 2y = -36 + 126

9x = 90

x = 10

Plug value of x back into to the equations to solve for y

3(10) + 2y = 36

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2y =6

y = 3

Optional

Plug x into the other equation to check for error

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120 + 2y =126

2y = 6

y = 3

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Answer:

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