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lutik1710 [3]
3 years ago
5

What is the value of x? 6+8z/2= 5x

Mathematics
2 answers:
statuscvo [17]3 years ago
8 0

Answer:

The answers is 3 hope this helped

Gala2k [10]3 years ago
5 0
X= 6/5 + 4z/5....................
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Which statement is true
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C.) because red is g and it goes up 6 right 6 an since blue is F it goes up 3 right 3 which would collide at the center
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In ΔMNO, the measure of ∠O=90°, ON = 35, NM = 37, and MO = 12. What is the value of the tangent of ∠M to the nearest hundredth?
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2.92 Rounded to the 100th

Step-by-step explanation:

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What is 49.6 divided by 7.8?
fomenos

Answer: 6.4

Step-by-step explanation: If rounding to one decimal place, your answer would be 6.4.

49.6 divided by 7.8 = 6.35897435...

Now, we see that after the 3 (The first decimal place) there is a five. Because we are rounding to the first decimal place the second decimal place will tell us to round up or down. In this case because it's a five, we would round up.

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1 year ago
Solve Y=3/2cot(1/2x)
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3 years ago
rotation of 90 degrees counterclockwise about the origin, point O, then a reflection across the x-axis reflection across the y-a
SpyIntel [72]

Answer:

The point O can be (x,y)  or (-x,y) or (-x,-y) or ( x,-y) reason being that you haven't given point O lies in which quadrant.

Rotation through 90° counter clockwise

(x,y) = (-y,x)

(-x,y)=(-y,-x)

(-x,-y)=(y,-x)

(x,-y) =(y,x)

Then Reflection across X axis has taken place.

(-y,x) = (-y,-x)

(-y,-x)=(-y,x)

(y,-x)=(y,x)

(y,x)=(y,-x)

Then a reflection across the y-axis has taken place.

(-y,-x)=(y,-x)

(-y,x) = (y,x)

(y,x) =(-y,x)

(y,-x)=(-y,-x)

Then a translation a units to the right and b units up has taken place.

(y,-x)=(y+a,-x+b)

(y,x) =(y+a, x+b)

(-y,x) =(-y+a,x+b)

(-y,-x)=(-y+a,-x+b)

Then a rotation of 180 degrees counterclockwise about the origin has taken place.

(y+a,-x+b)=[-(y+a),-(-x+b)]

(y+a, x+b)=[- (y+a), -(x+b)]

(-y+a,x+b)=[-(-y+a),-(x+b)]

(-y+a,-x+b) =[-(-y+a),-(-x+b)]

Now Again a reflection across the Y axis has taken place.

[-(y+a),-(-x+b)]=[(y+a),-(-x+b)]

[-(y+a),-(x+b)]=[(y+a),-(-x+b)]

[-(-y+a),-(x+b)]=[(-y+a),-(x+b)]

[-(-y+a),-(-x+b)]=[(-y+a),-(-x+b)]

Totally depends on value of a and b on which quadrant these point lies.



7 0
3 years ago
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