Number 3.) The answer to this one is x=-14
That is because when a line is undefined it goes as x = (whatever number it is on)
Currency Ln. is undefined and you have to find a line parallel so that's why it's x = -14
Number 4.)
So it says that the new street will be parallel to Market Blvd. meaning that they will have the same slope
Find the slope of Market Blvd.
Rise/Run
the slope is negative as it goes down from left to right
it goes down 7 and over 1
slope = -7
and it will pass through the point (-1, 5)
to find the y-intercept we plug in the points to y = mx + b
5 = -7(-1) + b
5 = 7 + b
subtract 7 from both sides
-2 = b
Plug all the info into the slope intercept we get:
y = -7x -2
So your answer is G
Number 5.)
If a line is parallel to another line, that means they have the same slope
So here you just need to find the slope of the line named "Bear Street"
Slope is the change in y over the change in x
or the rise/run
The rise is 1
and the run is 7
it is a positive slant as the line goes up from left to right
so the slope is
1/7
Or D.) 1/7
Hope this helps :)
Let us denote the semi arcs as congruent angles. This means that angles FEJ and EFJ are congruent (That is, they have the same measure). Since angles FEJ and EFJ have the same measure, this implies that sides EJ and FJ are equal. Since angles EJK and FJH are supplementary angles to angle EJF, this implies that EJK and FJH have the same measure.
Using the Angle Side Angle (SAS) criteria, we determine that triangles EKJ and triangle FJH are congruent. This implies that sides EK and FH are equal and that angles EKJ and FHJ are congruent. Note that angle EKJ is the same as EKF and that FHJ is the same as FHE.
Once again, since angles EKF and FHJ are congruent, and angle EKD is supplementary to the angle EKJ when angle FHG is supplementary to angle FHJ, then we have that angles EKD and angle FHG are congruent.
Using again the SAS criteria, we determine that triangles EKD and FHG are congruent.
From this reasoning, we have proved the following facts:
Triangle DEK is congruent to triangl GFH
Angle EKF is congruent to angle FHE
Segment EK is the same as segment FH
OK first convert one of the equations into Y=MX+b form
Y-2x = 3
Add 2X
Y = 2x +3
Now substitute this equation in the other one.
So it would be
3X - 2Y = 5
3X-2(2x+3) = 5
Now solve for y
3X - 4X - 6 = 5
-1X - 6 = 5
Add 6
-1X = 11
X = -11
Now substitute this into one of the equations
Y - 2X = 3
Y -2(-11) = 3
Y +22 = 3
y = 3-22
y = -19
