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jenyasd209 [6]
3 years ago
11

This question is tricky

Mathematics
1 answer:
grandymaker [24]3 years ago
8 0
I think it is c. because a+ - b+ = -8
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Irrational

Step-by-step explanation:

Since √3 is a non-terminating decimal (it repeats forever), it will be an irrational number.

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In circle Y, what is m &lt;1?<br> 37<br> 06<br> 0 25°<br> O 31°<br> 0 37°
jekas [21]

Answer:

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-------------------------

Hope it helps...

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8 0
3 years ago
Please help!! thank you.
Zina [86]

(A) Product of -2x^{3}+x-5 and x^{3}-3x-4 is:

(-2x^{3}+x-5)(x^{3}-3x-4)

=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)

=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)

=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20

=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20

=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20

(B) Yes.

Product of -2x^{3}+x-5 and x^{3}-3x-4 = Product of x^{3}-3x-4 and -2x^{3}+x-5 because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.



5 0
3 years ago
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