Let x represent amount invested in the higher-yielding account.
We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be
.
We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.
, where,
I = Amount of interest,
P = Principal amount,
r = Annual interest rate in decimal form,
t = Time in years.
We are told that interest rates are 6% and 10%.


Amount of interest earned from lower-yielding account:
.
Amount of interest earned from higher-yielding account:
.

Let us solve for x.



Therefore, the man invested $30,000 at 10%.
Amount invested in the lower-yielding account would be
.
Therefore, the man invested $60,000 at 6%.
79.881 hope this helps
i might be wrong
The value of x when y =4 is 2
<h3>How to solve for x?</h3>
An inverse proportion is represented as:
k = yx
Where
k represents the constant of proportion
When y = 2, x = 4.
So, we have:
k =2 * 4
k = 8
Substitute k = 8 in k = yx
So, we have:
yx = 8
When y = 4, we have:
4x = 8
Divide by 4
x = 2
Hence, the value of x when y =4 is 2
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