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Lelu [443]
3 years ago
13

Liza bought 5/8 pound of trail mix. She gives 2/8 pound of trail mix to michael. How much trail mix does liza have left?

Mathematics
1 answer:
cricket20 [7]3 years ago
8 0
Liza has 3/8 pounds of trail mix left. I just subtracted 5/8-2/8 since they have common denominators you keep the denominator the same and just subtract the numerators, so 5/8-2/8= 3/8 pounds.
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A school sing games played 160 games and won 65 percent of them how many games did the team win?
jonny [76]
The team won 104 games
160 * 0.65 = 104
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3 years ago
A bakery has d dozen eggs in one refrigerator and 3 fewer dozen eggs in another refrigerator. Which expressions correctly show h
san4es73 [151]

Answer:  2 d - 3

Step-by-step explanation:

Here, the number of dozen eggs in one refrigerator = d

According to the question,

There are 3 fewer dozen eggs in another refrigerator.

⇒ The number of eggs in another refrigerator = d - 3

Thus, the total dozen of eggs in both refrigerator = the number of dozen eggs in first refrigerator + the number of dozen eggs in second refrigerator

= d + d - 3

= 2 d - 3

Which is the required expression.

3 0
3 years ago
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∆ABC is reflected about the line y = -x to give ∆A'B'C' with vertices
Ilia_Sergeevich [38]
Since A‘(-1,1) is on the line y=-x, reflecting it about the line doesn't change its coordinate, so A's coordinate is (-1,1). Reflecting B'(-2,1) about y=-x switches both the sign and the number of x and y, so B=(-1,2), and C'(-1,0) becomes C(0,1). Drawing out the graph with the points and the line helps.
4 0
3 years ago
pretende-se guardar um cano de 42cm de comprimento em uma caixa de ferramentas retangular, cuja as medidas são 36cm de comprimen
galina1969 [7]

Answer:

Step-by-step explanation:

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3 0
3 years ago
To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

3 0
3 years ago
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