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Troyanec [42]
2 years ago
5

Find the value of x in the isosceles triangle shown below. 13 V13 2

Mathematics
1 answer:
UNO [17]2 years ago
7 0

Answer:

<h3>x = 6</h3><h3></h3>

Step-by-step explanation:

use Pythagorean theorem:

a² + b² = c²

where a = 2

           b = x/2  

           c = √13

<u>plugin values into the formula:</u>

2² + (x/2)² = (√13)²

4² + <u>x² </u>= 13

       4

16 + x² = 13 (4)

x² = 52 - 16

x = √36

x = 6

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6×?×3=90 what's supposed to go in the ? Slot
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Answer:

5

Step-by-step explanation:

6 x 3 = 18

90 / 18 = 5

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3 years ago
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Find the perimeter of ΔNOP. Round your answer to nearest tenth if necessary. Figures are not necessarily drawn to scale
Morgarella [4.7K]

Answer:

P = 157.5 units

Step-by-step explanation:

7 0
3 years ago
At 12 noon in anchorage Alaska Janice noticed that the temperature outside was 12
Alisiya [41]
I assume that you want to know the temperature at a certain timing.
Well, you know that at 12:00 pm, the temperature was 12 F and that it decreases by a steady rate of 2 F each hour.

This means that at 1:00 pm, the temperature was 12-2 = 10 F
At 2:00 pm, the temperature was 10-2 = 8 F
At 3:00 pm, it was 8-2 = 6 F
.......and so on

You can follow this sequence to the timing you are looking for.
7 0
2 years ago
April shoots an arrow upward into the air at a speed of 32 feet per second from a platform that is 11 feet high. The height of t
dusya [7]

Answer:

27 ft

the maximum height of the​ arrow is 27 ft

Step-by-step explanation:

Given;

The height of the arrow is given by the function;

h(t) = -16t^2 + 32t + 11

Maximum height is at point when dh(t)/dt = 0.

Differentiating h(t), we have;

dh/dt = -32t + 32 = 0

Solving for t;

-32t = -32

t = -32/-32 = 1

t = 1 (time at maximum height is t = 1)

Substituting t=1 into h(t), to determine the value of maximum height;

h(max)= -16(1^2) + 32(1) + 11

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8 0
2 years ago
Last year, the volleyball team paid $5 pair for socks and $17 per pair for shorts on a total purchase of $315. This year they sp
vivado [14]

Answer:

Option E is correct.

12 pairs of socks and 15 pairs of shorts did team buy each year.

Step-by-step explanation:

Let the number of pairs of socks be x and the number pairs of shorts be y.

As per the statement:

Last year, the volleyball team paid $5 pair for socks and $17 per pair for shorts on a total purchase of $315.

⇒5x+17y = 315                   .....[1]

It is also given that: This year they spent $342 to buy the same number of socks and shorts, because the socks now cost $6 a pair and the shorts cost $18.

⇒6x + 18y = 342                   .....[2]

Multiply equation [1] by 6 both sides we get;

30x+102y = 1890                 .......[3]

Multiply equation [2] by 5 both sides we get;

30x +90y = 1710                   .....[4]

Subtract equation [4] from [3] we get;

12y =180

Divide both sides by 168 we get;

y = 15

Substitute the given values of y =15 in [1] we get;

5x+17(15) = 315

5x + 255 = 315

Subtract 255 from both sides we get;

5x = 60

Divide both sides by 5 we get;

x = 12

Therefore, 12 pairs of socks and 15 pairs of shorts did team buy each year.

3 0
3 years ago
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