Question

An energy inefficient incandescent light bulb uses a hot filament to produce a continuous spectrum. The temperature of the filament is typically about 2853 k. At what wavelength (in nanometers)is the light bulb the brightest?

Answer 1

Answer:

So the wavelength of light is 1015.7 nm

Explanation:

From Wein's displacement law, we can write the following formula;

$\lambda _{MAX}\times T=K$ here, $\lambda _{MAX}$ is the wavelength of maximum radiation in meters

T is the absolute temperature (in Kelvin) for maximum radiation

K is the constant has a value of $2.898\times 10^{-3}m-kelvin$

Given here,  T = 2853 K

And we need to find  $\lambda _{MAX}$

Putting the values in formula

$\lambda _{max}\times 2853=2.898\times 10^{-3}$

$\lambda _{max}=1.0157\times 10^{-6}m$

$\lambda _{max}=1015.7\times 10^{-9}m=1015.7nm$