1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
avanturin [10]
4 years ago
6

Z--3/4=6 1/2 Help I have homework

Mathematics
2 answers:
Andre45 [30]4 years ago
8 0
In my opinion, it is easier to use decimals than fractions, so first we are going to rewrite this equation with decimals instead of fraction values.

z - 0.75 = 6.5

To simplify this equation, we are going to add 0.75 to both sides of the equation, to cancel out this value on the left side.

z= 7.25

Your final answer is=7.25 or 7 1/4
GarryVolchara [31]4 years ago
6 0
Two negatives is a positive so the equation is Z+3/4=13/2
-3/4
Z=26/4-3/4
Z=23/4
You might be interested in
In how many ways can Joseph, Michael, Chris, Katherine, Rebecca and Kyle stand in a line?
Andrews [41]

Answer:

720

Step-by-step explanation:

I got it from Quora

We can use 6 people without repetition, which means we simply have to use counting principle 1.

A number of n objects can be arranged in n! ways.

Total number of combinations possibles = 6! =720

6 0
4 years ago
The square of a number decreased by 3 times the number 28 find all possible values for the number
stealth61 [152]

Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number  

Answer:

The possible values of number are 7 and -4

Solution:

Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

From given information,

square of a number decreased by 3 times the number = 28

a^2 - 3a = 28

a^2 - 3a - 28 = 0

Let us solve the above quadratic equation

\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Using the above formula,

\text { For } a^{2}-3 a-28=0 \text { we have } a=1, b=-3, c=-28

\begin{aligned}&a=\frac{-(-3) \pm \sqrt{(-3)^{2}-4(1)(-28)}}{2 \times 1}\\\\&a=\frac{3 \pm \sqrt{9+112}}{2}\\\\&a=\frac{3 \pm \sqrt{121}}{2}=\frac{3 \pm 11}{2}\\\\&a=\frac{3+11}{2} \text { or } a=\frac{3-11}{2}\\\\&a=7 \text { or } a=-4\end{aligned}

Thus the possible values of number are 7 and -4

5 0
3 years ago
What is 5.43 didided by 15
Nookie1986 [14]
Divided

5.43÷15=0.362
5 0
4 years ago
Read 2 more answers
If i= square root of -1, what is the value of i 3?
Furkat [3]
If  i = √-1 ,

then ...

i²  =  (√-1)²  =  -1

i³  =  - √-1  =  -i          <== the answer to the question

i⁴  =  (i²) · (i²)  =  (-1) · (-1)  =  1

and then the whole thing starts over again, for higher powers of  i .
6 0
4 years ago
Read 2 more answers
Ali salary is increased from 2600 to 3000 . How much is percentage increase​
nadezda [96]

Answer:

15.3 %

Step-by-step explanation:

400 / 2600 x 100 = 15.3 %

I hope im right!!

8 0
3 years ago
Read 2 more answers
Other questions:
  • Simplify completely.<br><br> (w^15/w^5)^4
    11·1 answer
  • Solve each system of equations using substitution. Show all work.
    6·1 answer
  • Refer to the following study and the SAS output:
    13·1 answer
  • What is equivalent to (1/4) to the -3 power
    15·2 answers
  • At the end of the summer, Jamie bought a $325 surfboard for $123.50. By what percent was the surfboard marked down?
    13·1 answer
  • NEED HELP PLEASE
    15·2 answers
  • The highest and lowest recorded temperatures for the state of Texas was 120F and -23F. Find the difference in these extreme temp
    8·1 answer
  • Which would be the answer? Tysm for whoever helps its greatly appreciated!
    12·2 answers
  • your bathtub is 2 feet wide, 6 1/2 feet long, and 2 feet, 9 inches deep when full how many cubic feet of water do you need to fi
    15·1 answer
  • What is the value of t in the equation 3(t − 4) = 2t + 1?
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!