Answer:
11 quarters
Step-by-step explanation:
If Thomas ignores the extra 3 dimes, he can arrange his coins in groups of 3 dimes and 1 quarter, each group valued at 55¢. It takes
... 6.05/0.55 = 11
groups to bring the total value to the $6.05 remaining after ignoring the extra dimes.
Thomas has 11 quarters and 36 dimes.
The answer is A) √3
cot(-5π/6)=1/tan(-5π/6)
=1/tan(-(5π/6)
Use the property: tan(-x)=-tan(x)
=1/tan(5π/6)
-(1/tan(5π/6))
tan(5π/6)=-√3/3
-(1/-√3/3)
-(1/-√3/3)
=√3
I hope this helps you
Area=length ×width
30 1/3=30.3+1/3=91/3
6 1/2=6.2+1/2=13/2
91/3=13/2.width
width =7.13.2/3.13
width =14/3
width = 4 2/3
Answer:
Is B (-2,-1),(0,0),(2,1)
Step-by-step explanation:
x y
-2 -1
0 0
2 1
I think!!??
donuts and cream puffs were 45 & 4 respectively !
<u>Step-by-step explanation:</u>
Here we have , twice the number of donuts was only 6 less than 24 times the number of cream puffs. 10 times the number of cream puffs was only 5 less than the number of donuts We need to find how many donuts and cream puffs were there . Let's find out:
Let number of donuts and cream puffs are x & y respectively ! So ,
- twice the number of donuts was only 6 less than 24 times the number of cream puffs
According to this statement equation is :
⇒ 
⇒
................(1)
- 10 times the number of cream puffs was only 5 less than the number of donuts
According to this statement equation is :
⇒ 
⇒
................(2)
Equation (1) & (2) :
⇒ 
⇒ 
⇒ 
Putting
in
:
⇒ 
⇒ 
Therefore , donuts and cream puffs were 45 & 4 respectively !