Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:12
Step-by-step explanation:
Answer:
-6
Step-by-step explanation:
imagine you're on a line graph you start at zero and then go backward 15 spaces and move forward 9 spaces where does that leave you
6+6
8+4
9+3
10+2
11+1
Hope this helps!
Answer:
Step-by-step explanation:
Move all terms to one side
4x^2 + 4x + 5 = 0
Plug into quadratic formula
x = (-4 <u>+</u> 
) / 2(4)
= (-4 <u>+</u> 
)/8
At this point, there are no real answers. The roots to this equation are complex.
x = (-4 <u>+</u> 8i)/8
= (-1 <u>+</u> 2i)/2
