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alexgriva [62]
3 years ago
12

How would i describe the relationship?

Mathematics
1 answer:
lara31 [8.8K]3 years ago
6 0

Answer:

12

Step-by-step explanation:

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How to solve this problem?
faust18 [17]
54 = 27 x 2. Third root of 27 = 3 because 3 x 3 x 3 =2. So you get 3root2
4 0
3 years ago
If A = (9, 18) and B = (1, 12), what is the length of AB
musickatia [10]

Answer:

the length is 10

Step-by-step explanation:

√(1 - 9)2 + (12 - 18)2 =

√(-8)2 + (-6)2 = √64 + 36 =

√100= 10

8 0
3 years ago
Read 2 more answers
W<br>3:<br><img src="https://tex.z-dn.net/?f=2x%28x%20-%203%29%20%3D%200%20" id="TexFormula1" title="2x(x - 3) = 0 " alt="2x(x -
katrin [286]

Answer:

x = 3, x = 0

Step-by-step explanation:

To solve these factored equations, just divide each part by zero and solve.

2x(x-3) = 0 → (x-3) = 0, and 2x = 0.

(x-3) = 0 → x - 3 + 3 = 0 + 3 → <u>x = 3.</u>

2x = 0 → 2x/2 = 0/2 → <u>x = 0.</u>

5 0
3 years ago
Can you help with this one too.
lidiya [134]

Answer:

Odd, Even

Step-by-step explanation:

A function is said to be an Even function if it follows f(-x) = f(x).

A function is said to be an Odd function if it follows f(-x) = -f(x).

It means we can plug -x in place of x and check if it comes out to be f(x) or -f(x) i.e. y or -y?

Given y = sin³x/cos³x and y = 1/sec³x

y = sin^3x/cos^3x\\f(x) = sin^3x/cos^3x\\f(-x) = sin^3(-x)/cos^3(-x)\\f(-x)= (sin(-x))^3/(cos(-x))^3\\f(-x)=(-sin(x))^3/(cos(x))^3\\f(-x)=-sin^3x/cos^3x\\f(-x)=-f(x)\\Odd\; function

y=1/sec^3x\\f(x)= 1/sec^3x\\f(x)=cos^3x\\f(-x)=cos^3(-x)\\f(-x)=(cos(-x))^3\\f(-x)=(cos\;x)^3\\f(-x)=cos^3x\\f(-x)=f(x)\\Even\; function

Hence, first function is Odd, second function is Even.

3 0
2 years ago
200% of d is 18. what is it <br>​
Westkost [7]

Answer:

36 is d

Step-by-step explanation:

4 0
2 years ago
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