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KATRIN_1 [288]
1 year ago
9

HELP ASAP!!!The circumference of a circle is 6 pi meters. Find the radius of the circle

Mathematics
1 answer:
tatiyna1 year ago
6 0

3

Step-by-step explanation:

radius is just the diameter cut in half.

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What equation best represents the following sentence?
Tems11 [23]

Answer:

2n + 1 to find the first odd number.

Step-by-step explanation:

that is it

8 0
3 years ago
1+4=5<br> 2+5=12<br> 3+6=21<br> 8+11=?
MariettaO [177]
Oh, I SEE what da pattern is! =D
You see, like in this problem:
2 + 5 = 12
They did 5 times 2 = 10, plus da 2 in da problem = 12.
Same with 3 + 6 = 21, 6 times 3 = 18, 18 plus da 3 given in da problem = 21.
Just like 1 + 4 = 5, 4 times 1 = 4, plus da 1 in da problem = 5.
SO,
with that strategy, 8 +11 = 96, because 8 times 11 = 88, plus da 8 given in da problem = 96.
I hope I helped! =D
6 0
3 years ago
If there are 3 people in a room, the probability that they all have the same birthday is
Nostrana [21]
There is .82% chance they will have the same bdays
7 0
3 years ago
The question and answers are there
Vlada [557]
D) initial value of 60 and multiplying by 1/3
8 0
3 years ago
Scores on a final exam taken by 1200 students have a bell shaped distribution with mean=72 and standard deviation=9
SVETLANKA909090 [29]

Answer:

a. 72

b. 816

c. 570

d. 30

Step-by-step explanation:

Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.

Please refer the figure for a better understanding.

a. In a normal distribution, Mean = Median = Mode

Therefore, Median = Mean = 72

b. We have to know that 68% of the values are within the first standard deviation of the mean.

i.e., 68% values are between Mean $ \pm $ Standard Deviation (SD).

Scores between 63 and 81 :

Note that 72 - 9 = 63 and

72 + 9 = 81

This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.

Now, Scores between 63 and 81 = $ \frac{68}{100} \times 1200 $

= 68 X 12 = 816.

That means 816 students have scored between 63 and 81.

c. We have to know that 95% of the values lie between second Standard Deviation of the mean.

i.e., 95% values are between Mean $ \pm $ 2(SD).

Note that 90 = 72 + 2(9) = 72 + 18

Also, 54 = 63 - 18.

Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to $ \frac{95}{2} \% $ of the values.

Therefore, Scores between 72 and 90 = $ \frac{95}{2(100)} \times 1200 = \frac{95}{200} \times 1200  $

$ \implies 95 \times 12 $ = 570.

That is a total of 570 students scored between 72 and 90.

d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.

In this case, 5 % of the values lie between below 54 and above 90.

Since, we are asked to find scores below 54. It should be 2.5% of the values.

So, Scores below 54 = $ \frac{2.5}{100} \times 1200 $

= 2.5 X 12 = 30.

That is, 30 students have scored below 54.

8 0
3 years ago
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