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bezimeni [28]
3 years ago
12

Please help, if you know how to do proofs in Geometry !

Mathematics
1 answer:
Oduvanchick [21]3 years ago
8 0

Step-by-step explanation:

1. T is the midpoint of QR, U is the midpoint of QS, and V is the midpoint of RS.

This is the information given in the problem statement.

2. TU, UV, and VT are midsegments

Midsegments connect midpoints of opposite sides.  So TU, UV, and VT are midsegments.

3. TU = ½ RS, UV = ½ QR, and VT = ½ SQ

By Triangle Midsegment Theorem, a midsegment connecting the midpoints of two sides of a triangle is half the length of the third side.

4. TU/RS = 1/2, UV/QR = 1/2, VT/SQ = 1/2

Division property

5. TU/RS = UV/QR = VT/SQ

Transitive property

6. ΔQRS ~ ΔVUT

Since we've shown that the corresponding sides of these triangles are proportional, then by Converse of Similar Triangles Theorem, the triangles must be similar.

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6

Step-by-step explanation:

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Buses on your route run every 11 minutes from 7 AM to 11 AM arrive at the bus stop at 8:18 AM how long will you wait for a bus
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Your sentence is not complete.  Please proofread your questions before sharing them.  

I think you meant:
 
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4 years ago
Let f(x) = {(1, 11), (2, 12), (3, 13), (4, 12)}. Is this a function? *
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The sides of ∆ABC are 30 units, 40 units, and 60 units long. The corresponding sides of ∆XYZ are r times as long as the sides of
san4es73 [151]

Part a) Find the expression that gives the perimeter of ∆XYZ

we know that

Perimeter of triangle ABC is equal to

P=30+40+60\\ P=130\ units

In this problem ∆ABC and ∆XYZ are similar triangles

the scale factor is equal to r

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scale\ factor=r \\ \\ scale\ factor=\frac{perimeter\ triangle\  XYZ}{perimeter\  triangle\  ABC}  \\ \\ perimeter\ triangle\  XYZ=perimeter\  triangle\  ABC*scale factor\\ \\ perimeter\ triangle\  XYZ=130*r

therefore

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The expression that gives the perimeter of ∆XYZ is 130*r\ units

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scale\ factor=r \\ \\ scale\ factor^{2}=\frac{Area\ triangle\  XYZ}{Area\  triangle\  ABC}  \\ \\ Area\ triangle\  XYZ=Area\  triangle\  ABC*scale factor^{2}\\ \\ Area\ triangle\  XYZ=n*r^{2}\ units^{2}

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The expression that gives the Area of ∆XYZ is n*r^{2}\ units^{2}

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