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Dmitry [639]
3 years ago
15

H=3+14t-5t^2 What is its maximum height

Mathematics
1 answer:
timurjin [86]3 years ago
5 0

Answer:

12.8

Step-by-step explanation:

Given a parabola in standard form , ax² + bx + c : a ≠ 0

Then the x- coordinate of the vertex is

x_{vertex} = - \frac{b}{2a}

h = 3 + 14t - 5t² ← is in standard form

with a = - 5 and b = 14, thus

x_{vertex} = - \frac{14}{-10} = 1.4

Substitute t = 1.4 into h for maximum height

h = 3 + 14(1.4) - 5(1.4)²

   = 3 + 19.6 - 9.8 = 12.8

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292 students each get 10 ounces. How many ounces are needed?
sasho [114]

Answer:

2,920 ounces

Step-by-step explanation:

To find this, just multiply:

292 × 10 = 2,920

So, 2,920 ounces are needed

Hope this helps :)

7 0
3 years ago
What is the area, in square inches, of the figure shown here?
andreev551 [17]
The area of the central rectangle = 5 * 3 = 15 ins^2

area of each triangle = 1/2*3*3 = 4.6 ins^2

Total area = 2*4.5 + 15  = 24 ins^2 (answer)
3 0
3 years ago
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You work for a printing company.Your machine can prine 80 posters per hour. You printed 600 posters. How many hours did you work
AlexFokin [52]
The amount of hours you worked would be 7.5, you divide 600 by 80.
7 0
3 years ago
A college conducts a common test for all the students. For the Mathematics portion of this test, the scores are normally distrib
Jet001 [13]

Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 502, \sigma = 115

The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:

X = 590:

Z = \frac{X - \mu}{\sigma}

Z = \frac{590 - 502}{115}

Z = 0.76

Z = 0.76 has a p-value of 0.7764.

X = 400:

Z = \frac{X - \mu}{\sigma}

Z = \frac{400 - 502}{115}

Z = -0.89

Z = -0.89 has a p-value of 0.1867.

0.7764 - 0.1867 = 0.5897 = 58.97%.

58.97% of students would be expected to score between 400 and 590.

More can be learned about the normal distribution at brainly.com/question/27643290

#SPJ1

6 0
2 years ago
What percent of the volunteers was at least 15 years old but no more than 24 years old?
viva [34]

Answer:

i think it is 1% sry if wrong  

Step-by-step explanation:

4 0
3 years ago
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