H=3+14t-5t^2 What is its maximum height
1 answer:
Answer:
12.8
Step-by-step explanation:
Given a parabola in standard form , ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= -
h = 3 + 14t - 5t² ← is in standard form
with a = - 5 and b = 14, thus
= -
= 1.4
Substitute t = 1.4 into h for maximum height
h = 3 + 14(1.4) - 5(1.4)²
= 3 + 19.6 - 9.8 = 12.8
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Answer:
Where h,k represent the vertex and we got:
(5,6)
Step-by-step explanation:
We have this original function given :
And we want to find the vertex for this new function and we have:
And solving the square we got:
And adding similar terms we got:
Now we can complete the square like this:
The general equation is given by:
Where h,k represent the vertex and we got:
(5,6)