H=3+14t-5t^2 What is its maximum height
1 answer:
Answer:
12.8
Step-by-step explanation:
Given a parabola in standard form , ax² + bx + c : a ≠ 0
Then the x- coordinate of the vertex is
= -
h = 3 + 14t - 5t² ← is in standard form
with a = - 5 and b = 14, thus
= -
= 1.4
Substitute t = 1.4 into h for maximum height
h = 3 + 14(1.4) - 5(1.4)²
= 3 + 19.6 - 9.8 = 12.8
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Step-by-step explanation:
Given:
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