Answer:
<h2>
<em><u>$23.40 </u></em></h2>
Step-by-step explanation:
<em><u>Given,</u></em>
Cost price of 8 cakes = $62.40
<em><u>So,</u></em>
Cost price of 1 cake = $ 
<em><u>Therefore,</u></em>
Cost price of 3 cakes
= $( × 3)
- <em>[On dividing 62.40 by 8]</em>
= $(7.80 × 3)
- <em>[On multiplying]</em>
= $23.40
<em><u>Hence,</u></em>
<em><u>The required cost of 3 cakes is $23.40 (Ans)</u></em>
90. Add the zero in front of the 9.
0.10×16,050+0.28×(134,899−16,050)
=34,882.72
Answer:
8 one-dollar bills
3 five-dollar bills
2 ten-dollar bills
Step-by-step explanation:
Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13
x + 5y + 10z = 43
x = 4z
x + y + z = 13
x + 5y + 10z = 43
x + 0y - 4z = 0
x + y + z = 13
5y + 14z = 43
-y - 5z = -13
5y + 14z = 43
-5y - 25z = -65
-11z = -22
z = 2
x = 4z
x = 4*2 = 8
x + y + z = 13
8 + y + 2 = 13
10 + y = 13
y = 3
