Ask question

Ask question

All categories

3 years ago

12

Solve the following equation, answer as a reduced, mixed number. Then place the correct number in the box provided. 4(3 - 2x) =

15

2 answers:

valentinak56 [21]3 years ago

8 0

Answer:

x = -3/8

Step-by-step explanation:

4(3 - 2x) = 15

Distribute

12 -8x = 15

Subtract 12 from each side

12-8x-12 =15-12

-8x =3

Divide by -8

-8x/-8 = 3/-8

x = -3/8

vfiekz [6]3 years ago

7 0

The correct answer is: -3/8

You might be interested in

Kamila [148]

Answer:

Part B: $\displaystyle [1, 2]$

Part A: Set both equation equal to each other by Substitution, since our <em>y-values</em> are already given to us.

Step-by-step explanation:

6x - 4 = 5x - 3

- 6x + 3 - 6x + 3

____________

$\displaystyle -1 = -x; 1 = x$

Plug this coordinate back into the above equations to get the <em>y-coordinate</em><em> </em>of 2.

<em>y</em><em> </em><em>=</em><em> </em><em>mx</em><em> </em><em>+</em><em> </em><em>b</em><em> </em>[where<em> </em><em>b</em><em> </em>is the y-intercept and the rate of change (slope) is represented by <em>m</em>]

$\displaystyle y = 5x - 3; [0, -3]; 5 = m \\ y = 6x - 4; [0, -4]; 6 = m$

I am joyous to assist you at any time.

3 0

3 years ago

If A = { a, b, c, d} and B = {b,c,d,e} Then find AnB {b,c,d}<br>

vladimir1956 [14]

Answer:

AnB = ( b, c, d ) is the answer.

Hope this will help u

5 0

3 years ago

What's the quadratic equation?

erma4kov [3.2K]

The standard form of the quadratic equation is ax^2 + bx + c. In vertex form, it's y = a(x – h)2 + k.
The graph of a quadratic equation is a parabola, which looks like a u. If <em>a</em> is negative then it's an upside down u.

6 0

3 years ago

Read 2 more answers

Find the area of the rectangle

aksik [14]

Hope it works for you

4 0

3 years ago

mrs.beluga is driving on a snow covered road with a drag factor of 0.2. she brakes suddenly for a deer. The tires leave a yaw ma

Aneli [31]

First, we are going to find the radius of the yaw mark. To do that we are going to use the formula: $r= \frac{c^2}{8m} + \frac{m}{2}$
where
$c$ is the length of the chord
$m$ is the middle ordinate
We know from our problem that the tires leave a yaw mark with a 52 foot chord and a middle ornate of 6 feet, so $c=52$ and $m=6$ . Lets replace those values in our formula:
$r= \frac{52^2}{8(6)} + \frac{6}{2}$
$r= \frac{2704}{48} +3$
$r= \frac{169}{3} +3$
$r= \frac{178}{3}$

Next, to find the minimum speed, we are going to use the formula: $s= \sqrt{15fr}$
where
$f$ is <span>drag factor
</span> $r$ is the radius
We know form our problem that the drag factor is 0.2, so $f=0.2$ . We also know from our previous calculation that the radius is $\frac{178}{3}$ , so $r= \frac{178}{3}$ . Lets replace those values in our formula:
$s= \sqrt{(15)(0.2)( \frac{178}{3}) }$
$s= \sqrt{178}$
$s=13.34$ mph

We can conclude that Mrs. Beluga's minimum speed before she applied the brakes was 13.34 miles per hour.

8 0

3 years ago