Once a commercial plane reaches the desired altitude,

An acute triangle has a side measuring 10 cm and 16 cm. The legnth of the third side is unknown. Which best describes the range

svlad2 [7]

it is from the range of 6<x<26. I hope this helps. Could I possibly get brainliest?

5 0

3 years ago

Read 2 more answers

A car is on a driveway that is inclined 10 degrees to the horizontal. A force of 490 lb is required to keep the car from rolling

lara31 [8.8K]

Answer:

a) weight of the car = 2816,1 lbs

b) 2773 lbs

Step-by-step explanation:

The equilibrium force is 490 lbs. That force keep the car at rest, then

∑ Fy = 0 and ∑Fx = 0

Forces acting on the car:

The external force 490 lbs

weight of the car uknown

Normal force

sin∠10° = 0,174

cos∠10° = 0.985

∑Fx = 0 mg*sin10°- 490 = 0 ∑Fy = 0 mg*cos10° - N = 0

mg*0,174= 490

mg = 490 / 0,174

mg = 2816,1 lbs

weight of the car = 2816,1 lbs

The Normal force

mg*cos10° - N = 0 2816,1 * 0,985 = N

N = 2773 lbs

Then equal force in magnitude and in opposite direction will car exets on the driveway

3 0

3 years ago

Find the axis of symmetry of the parabola below <br> A-Y=2<br> B-X=2<br> C-X=1<br> D-Y=1

victus00 [196]

The axis of symmetry is given by the line x = a (where a is equivalent to the x-value of the turning point of the parabola) and can be viewed as the line about which the parabola is symmetric; in this case, the parabola has an axis of symmetry of x = 2, thus the answer is B

8 0

3 years ago

Question 6 The mineral content of a particular brand of supplement pills is normally distributed with mean 490 mg and variance o

AysviL [449]

Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 490 mg and variance of 400.

This means that $\mu = 490, \sigma = \sqrt{400} = 20$