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3 years ago

HELP MEEE RNNNNNNNNNNNNN

Mathematics

2 answers:

zhannawk [14.2K]3 years ago

8 0

Answer is B or 7 units x 4 units

dolphi86 [110]3 years ago

5 0

As this rectangle has it's sides parallel to x axis and y axis

it is easy to find the length of it's sides by counting the number of blocks on each sides.

Let us first find co ordinates of all four points

we would calculate them left and right and up down direction from the origian ( the cross point of x and y axis )

A : it is 2 unit left 2 unit up ( -2 , +2 )

B is 5 unit right 2 unit up ( +5 ,+2)

C is 5 unit right 2 unit down ( +5,-2)

D is 2 unit left 2 unit down ( -2,-2)

Let us now find the distance AB : A is 2 unit left B is 5 unit right so length AB= 2+5 = 7

Let us now find distance AD : A is 2 unit up and D is 2 unit down

so length AD= 2+2= 4

Answer should be 7 x 4 units

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3 years ago

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guapka [62]

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3 0

3 years ago

The function f(x)f(x) is a quartic function and the zeros of f(x)f(x) are -6−6, -5−5, -2−2 and 11. Assume the leading coefficien

Luden [163]

<h2>Answer: </h2>

$\boxed{f(x) = 11x^4 + 22x^3 - 1001x^2 - 5632x - 7260}$

<h2>Explanation: </h2>

A quartic function is a function given by the the following equation in standard form:

$f(x)=a_{4}x^4+a_{3}x^3+a_{2}x^2+a_{1}x+a_{0} \\ \\ \\ Where: \\ \\ a_{4},a_{3},a_{2},a_{1},a_{0} \ \text{are constant} \\ \\ \text{and} \ a_{4} \ \text{is the leading coefficient}$

From the statement we must assume the leading coefficient of f(x) is 11, so:

$a_{4}=11$

The zeros are:

$x=-6 \\ \\ x=-5 \\ \\ x=-2 \\ \\ x=11$

So, we can write:

$f(x)=11(x-(-6))(x-(-5))(x-(-2))(x-11) \\ \\ \\ So: \\ \\ \mathrm{Rule}:-\left(-a\right)=a \\ \\ \\ Then: \\ \\ f(x)=11\left(x+6\right)\left(x+5\right)\left(x+2\right)\left(x-11\right)$

$Expand:\left(x+6\right)\left(x+5\right):\ x^2+11x+30: \ \text{Distributive Property} \\ \\ \\ Then: \\ \\ f(x)=11\left(x^2+11x+30\right)\left(x+2\right)\left(x-11\right) \\ \\ \\ Expand:\left(x^2+11x+30\right)\left(x+2\right):\ x^3+13x^2+52x+60: \ \text{Distributive Property} \\ \\ \\ Then: \\ \\ f(x)=11\left(x^3+13x^2+52x+60\right)\left(x-11\right)$

$Expand: \left(x^3+13x^2+52x+60\right)\left(x-11\right):\ x^4+2x^3-91x^2-512x-660 \\ (Distributive \ property)$

Finally:

$f(x) = 11(x^4 + 2x^3 - 91x^2 - 512x - 660) \\ \\ \boxed{f(x) = 11x^4 + 22x^3 - 1001x^2 - 5632x - 7260}$

3 0

3 years ago

14 ten thousands<br> + 12 thousands =

vodka [1.7K]

152,000

is the correct answer

6 0

4 years ago

(08.07 HC)

katovenus [111]

Answer:

Below in bold.

Step-by-step explanation:

Part A

At the x-intercepts f(x) = 0, therefore:

2x^2 - 3x - 5 = 0

(2x - 5)(x + 1) = 0

x = 5/2, -1)

So the x intercepts are (-1, 0) and (5/2, 0).

Part B

The Coefficient of x^2 is positive ( it is 2) So the graph opens upwards and the vertex will be a minimum.

Convert f(x) to vertex form, by completing the square:

f(x) = 2x^2 - 3x - 5

= 2(x^2 - 3/2x) - 5

= 2[(x - 3/4)^2 - 9/16] - 5

= 2(x - 3/4)^2 -18/16 - 80/16

= 2(x - 3/4)^2 - 49/8

So the coordinates of the vertex are

(3/4, -49/8) or

(0.75, -6.125) in decimal form.

Part C

To graph f(x) you would first mark the points on the x axis which we found in Part 1 and the vertex found in Part 2. This vertex will be the bottom of the 'U'.

The graph is a parabola shaped roughly like a U, and will be symmetrical about the line x = 0.75 (which passes through the vertex).

You would also plot 2 more points above the x axis so as to get an accurate graph. 1 would be to the left of the line of symmetry and 1 to its right.

Suggest x = - 2 and calculate f(-2) = 2(-2)^2 - 3(-2) - 5 = 11.

- that is the point (-2,11) and the other would be x = 4, f(x) = 15. (4, 15)

Once you have plotted these points draw a smooth u shaped curve through them.

3 0

2 years ago