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Kazeer [188]
3 years ago
13

Helppppppppppppppppppppppp meeeeeeee

Mathematics
2 answers:
butalik [34]3 years ago
6 0
A) would be correct
pishuonlain [190]3 years ago
3 0

Answer:

A I think

Step-by-step explanation:

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Find the domain x^2-25/2
Mumz [18]
For this, I am assuming that -25/2 is not a part of the exponent(although in future questions you should make this clear by using parenthesis.

When I do problems like this, I come to CBAD.  where the variables are y=A(Bx+C)+D

CBAD helps significantly in domain and range problems where there is a well known parent function.  (y=x^2, y=sqrt(x), y=1/x, y=x, etc).  Basically, if there is a parent function with slight additions(y=2*x^2, y=sqrt(x+1), y=1/(5x), y=3x, etc)

This works that in the order, a C term shifts the graph horizontally in the opposite direction expected (a negative number will shift right, a positive number will shift left).  For example, if C is -2, the graph of the parent function will shift right 2.
Then, a B term dilates(changes the horizontal size of the graph) by the factor 1/B(every x value is multiplied by 1/B).  Thus a B >1 will shrink the graph horizontally, and a 0<B<1 with stretch the graph horizontally.  If B is negative, it reflects the graph over the y axis and then either shrinks or stretches horizontally.  If B is 1, nothing changes.
Then, a A term dilates(changes the horizontal size of the graph) by the factor A(every y value is multiplied by A).  Thus a A >1 will stretch the graph vertically, and a 0<A<1 with shrink the graph vertically.  If A is negative, it reflects the graph over the x axis and then either shrinks or stretches vertically.  If A is 1, nothing changes.
Finally, a D term shifts the graph vertically in the direction expected (a negative number will shift down, a positive number will shift up).  For example, if D is -2, the graph of the parent function will shift down 2.

<u>Warning </u><u></u><u>CBAD must be performed in the order C-B-A-D</u>

Now that you know these simple rules and can memorize the few parent functions, you can figure out the domain and range of almost any function.  

In your case, the function x^(2)-25/2 is not much different than x^2, an upwards facing parabola centered at (0,0).  In fact, there is only one transformation, D, because C=0 (it is not shown), B=1(it is not shown), and A=1(it is not shown).  Thus the only difference between your graph and the parent function is that yours is shifted down by 25/2.  

For this reason, because the domain of x^2 is not restricted (it includes all real numbers), the domain of your new function is not restricted (it includes all real numbers).
8 0
3 years ago
A barge moves 7km/hr in still water. It travels 45km upriver and 45km downriver in a total time of 14 hr. What is the speed of t
hodyreva [135]

Answer:

Step-by-step explanation:

2(3x−5)+4x−10=4x+2(x+6)

Step 1: Simplify both sides of the equation.

2(3x−5)+4x−10=4x+2(x+6)

(2)(3x)+(2)(−5)+4x+−10=4x+(2)(x)+(2)(6)(Distribute)

6x+−10+4x+−10=4x+2x+12

(6x+4x)+(−10+−10)=(4x+2x)+(12)(Combine Like Terms)

10x+−20=6x+12

10x−20=6x+12

Step 2: Subtract 6x from both sides.

10x−20−6x=6x+12−6x

4x−20=12

Step 3: Add 20 to both sides.

4x−20+20=12+20

4x=32

Step 4: Divide both sides by 4.

4x/4 =32/4

x=8

8 0
3 years ago
Which expression is eqivilent to 4.8 +2.2w - 1.4w + 2.4
yan [13]

Answer:

kmjnhbgvfcdxszxcvgbhnjmk,lkjhgfd

Step-by-step explanation:

8 0
3 years ago
Help me out please?<br>chapter : exponents and powers​
belka [17]

Answer:

\frac{125}{27}

Step-by-step explanation:

\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}

Lets expand all the composite numbers into prime numbers.

=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}

Lets cancel 2^{-4} from numerator and denominator.

=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}

Using laws of exponents , lets solve this.

=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}

=> \frac{3^{-3} \times 5^{1}}{5^{-2}}

=> 3^{-3} \times 5^{[1 - (-2)]}

=> 3^{-3} \times 5^{3}

=> \frac{5^3}{3^3} = \frac{125}{27}

4 0
3 years ago
Read 2 more answers
Diane received 300 votes in the election for student council president. That was 60% of the students who voted election. How man
VikaD [51]

Answer:

  500

Step-by-step explanation:

The problem statement tells you ...

  300 = 0.60×voters

Dividing by the coefficient of the variable gives ...

  300/0.60 = voters = 500

500 students voted in the election.

8 0
3 years ago
Read 2 more answers
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