Not sure the question but the only one that makes since is Line 1....
3*x^2 =6x^2
3*2x=6x
and the -7 its just in a different form
Answer:
put -2 in -2 / put -2 again in same spot and again just do it for 3 times then 1/3 in the middle of 0 and -2 but a bit closer to the -2
Step-by-step explanation:
Answer:
$0.67
Step-by-step explanation:
Divide 8(dollars) by 12 (donuts) and you get 0.66666666666666666666666666666667
But, round it and you get .67
Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
