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X equals 38. That means, angle R is 38, angle P is 69, and angle Q is 73.
You get x=38 by doing x+35+x+2x-7 = 180
*Hope this helps!*
Answer:
Step-by-step explanation:
R = (5+T)P/3
3R = (5+T)P
3R/ (5+T) = P
![P = \frac{3R}{(5+T) }](https://tex.z-dn.net/?f=P%20%3D%20%20%20%20%5Cfrac%7B3R%7D%7B%285%2BT%29%20%7D)
Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
![7x-9+4x+22 = 90](https://tex.z-dn.net/?f=7x-9%2B4x%2B22%20%3D%2090)
or, ![11x = 90-22+9](https://tex.z-dn.net/?f=11x%20%3D%2090-22%2B9)
or, ![11x = 77](https://tex.z-dn.net/?f=11x%20%3D%2077)
or, ![x = \frac{77}{11}](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B77%7D%7B11%7D)
or, ![x = 7](https://tex.z-dn.net/?f=x%20%3D%207)
Substituting the value of
in ∠QPR we get,
∠QPR = ![7(7)-9](https://tex.z-dn.net/?f=7%287%29-9)
or, ∠QPR = ![40^\circ](https://tex.z-dn.net/?f=40%5E%5Ccirc)
Hence,
The value of ∠QPR is 40°.
Since you're adding x feet to the length which is 12 feet:
New area: (12+x)10.5