Answer:
97,99,101,103
Step-by-step explanation:
Let x = first odd integer
x+2 = 2nd odd integer
x+4 = 3rd odd integer
x+6 = 4th odd integer
Sum of 4 odd integers is 400
x+ (x+2) + (x+4)+(x+6) = 400
Combine like terms
4x +12 = 400
Subtract 12 from each side
4x+12-12 = 400-12
4x = 388
Divide by 4 on each side
4x/4 = 388/4
x=97
The first integer is 97
The 2nd is 97+2 =99
The third ix 97+4 = 101
The 4th is 97+6 = 103
X² <span>− 3x − 70=0
</span>x² + 7x - 10x − 70=0
x(x+7) - 10(x+7) = 0
(x+7)(x-10) = 0
x + 7 = 0 or x - 10 = 0
x = -7 x = 10
Answer: x=-7, x=10
i will solve it first i need full form
I think the answer is G.
I think this because of the fact families (like my elementary teacher used to say)
It’s like about multiplication of fact families so make it where it would have fact families with those numbers as the sums.
I hope this helps! Be safe out there.
