The probability that a random alcoholic can kick the habit without professional help is 0.273 .
<h3>What is Probability ?</h3>
Probability is the study of likeliness of an event to happen.
It has a range of 0 to 1 , where 0 indicates uncertainty and 1 indicates certainty.
It is given that
The alcoholics that need professional help to stop drinking is 72.7 %
Therefore the probability of this is 72.7 /100 = 0.727
The probability that they will not need professional help is given by
q = 1 - p
q = 1 -0.727
q = 0.273
Therefore the probability that a random alcoholic can kick the habit without professional help is 0.273 .
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Log5 x=4 logx 5
Ln x/ln5=4(ln5 / ln x) logx z=ln x / ln z
least common multiple=ln5 * ln x
ln²x=4ln²5
√(ln² x)=√(4 ln²5)
ln x=2ln 5
x=e^2ln5=25
Answer: x=25.
Pretty sure the answer is k