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Brums [2.3K]
3 years ago
10

(25POINTS)Helpppp quickkk!!!The probability of getting a number divisible by 3 is 3/10 using a game spinner.The denominator of t

hat probability is?

Mathematics
2 answers:
olganol [36]3 years ago
6 0

Answer:

10

Step-by-step explanation:


Korolek [52]3 years ago
4 0

Answer:

I think the answer is D.

Step-by-step explanation:

I think the answer is D. is because it says "the total number of outcomes" and I think the denominator is just that.

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Last onss<br><br>please help me ​
Tpy6a [65]

Answer:

50000 i think and i hope it helps i think it helps idk im tired okay

Step-by-step explanation:

8 0
3 years ago
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a survey amony freshman at a certain university revealed that the number of hours spent studying the week before final exams was
Marat540 [252]

Answer:

Probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

Step-by-step explanation:

We are given that the number of hours spent studying the week before final exams was normally distributed with mean 25 and standard deviation 15.

A sample of 36 students was selected.

<em>Let </em>\bar X<em> = sample average time spent studying</em>

The z-score probability distribution for sample mean is given by;

          Z = \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = population mean hours spent studying = 25 hours

            \sigma = standard deviation = 15 hours

            n = sample of students = 36

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the average time spent studying for the sample was between 29 and 30 hours studying is given by = P(29 hours < \bar X < 30 hours)

    P(29 hours < \bar X < 30 hours) = P(\bar X < 30 hours) - P(\bar X \leq 29 hours)

      

    P(\bar X < 30 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } < \frac{ 30-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z < 2) = 0.97725

    P(\bar X \leq 29 hours) = P( \frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } }} } \leq \frac{ 29-25}{\frac{15}{\sqrt{36} } }} } ) = P(Z \leq 1.60) = 0.94520

                                                                    

<em>So, in the z table the P(Z </em>\leq<em> x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2 and x = 1.60 in the z table which has an area of 0.97725 and 0.94520 respectively.</em>

Therefore, P(29 hours < \bar X < 30 hours) = 0.97725 - 0.94520 = 0.0321

Hence, the probability that the average time spent studying for the sample was between 29 and 30 hours studying is 0.0321.

7 0
3 years ago
#89 will give brainliest for best answer!​
Lady_Fox [76]

Answer:

Median: 11

Range: 12

25th Percentile: 9

75th Percentile: 14

Interquartile Range: 5

Step-by-step explanation:

The median is the line in the 'middle' of the box. The range is the largest number minus the smallest number. 25th Percentile is the first line of the box, 75th is 3rd line. IQR is the 75th Percentile - 25th Percentile.

Hope this helps! :)

6 0
2 years ago
Please help asap!!! DX DX DX
Gnoma [55]
I believe the answer is C becuz i had that same answer and question so I HOPED I HELPED AND SMASH THAT THANKS BUTTON AND ADD ME AS A FRIEND
8 0
3 years ago
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Solve: 51 ÷ [(-15) + (-2)
kari74 [83]
Dude at the top correct
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3 years ago
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