1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vanyuwa [196]
3 years ago
15

300% of what number is 51?

Mathematics
1 answer:
Anarel [89]3 years ago
8 0
Set up an equation:
51=3x
17=x
x=17
300% of 17 is 51
You might be interested in
3a−15=4a−3a I NEED HELP WITH THIS ASAP PLZ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
GaryK [48]

Answer:

a = 15/2

Step-by-step explanation:

3a−15=4a−3a

Combine like terms

3a - 15 = a

Subtract 3a from each side

3a-3a−15=a−3a

-15 = -2a

Divide each side by -2

-15/-2 = -2a/-2

15/2 =a

8 0
3 years ago
Read 2 more answers
What is <br> 7/3(x-1)+1=3(x+1
madreJ [45]

Answer:

x = -13/2 = -6.500

Step-by-step explanation:

Just use tiger algebra solver that is what I use it is much easier.

3 0
3 years ago
Read 2 more answers
What is the value of x 2.5(12.75x + 24.50)=188.75
Liono4ka [1.6K]
Divide by 2.5: 2.5(12.75x+24.50)/2.5 = 188.75/2.5 .

simplify: 12.75x + 24.50=75.5 .

subtract 24.50 from both sides

simplify: 12.75x = 51 .

x= 4.
4 0
3 years ago
Read 2 more answers
Evaluate: 6 + [4(5 + 9)] step by step
jek_recluse [69]
The answer is 62
First you would have to add the ones in the parentheses 5+9=14 then you would have to multiply it by the 4 [4 14]giving you 56. Then 56+6= 62
8 0
3 years ago
A manufacturing company produces valves in various sizes and shapes. One particular valve plate is supposed to have a tensile st
ss7ja [257]

Answer:

Step-by-step explanation:

Hello!

The researcher wants to test if the valve plates manufactured have the expected tensile strength of 5 lbs/mm. So he took a sample of 42 valve plates and measured their tensile strength, obtaining a sample mean of X[bar]= 5.0611 lbs/mm and a sample standard deviation of S=0.2803 lbs/mm.

The study variable is:

X: tensile strength of a valve plate (lbs/mm)

The parameter of interest is the mean tensile strength of the valve plates, μ.

If the claim is that the valve plates of the sample have on average tensile strength of 5 lbs/mm, symbolically: μ = 5

a) The statistic hypotheses are:

H₀: μ = 5

H₁: μ ≠ 5

b) To determine the critical values and rejection region of a hypothesis test you need three to determine three factors of the hypothesis test:

1) The statistical hypothesis.

2) The significance level.

3) The statistic to use for the analysis.

The statistic hypothesis determines the number of critical values and the direction of the rejection region, in this case, the test is two-tailed you will have two critical values and the rejection region will be divided into two.

With the statistic, you will determine the distribution under which you will work and the significance level determines the probability of rejecting the null hypothesis.

To study the population mean you need that the variable of interest has at least a normal distribution, there is no information about the distribution of the study variable but the sample size is large enough n≥30, so you can apply the central limit theorem to approximate the distribution of the sample mean to normal: X[bar]≈N(μ;σ²/n)

Thanks to this approximation it is valid to use an approximation of the standard normal distribution for the test:

Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } }≈N(0;1)

The critical values are:

Z_{\alpha /2}= Z_{0.05}= -1.648

Z_{1-\alpha /2}= Z_{0.95}= 1.648

You will reject the null hypothesis if Z_{H_0}≤-1.648 or if Z_{H_0}≥1.648

You will not reject the null hypothesis if -1.648<Z_{H_0}<1.648

c)

Z_{H_0}= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }=  \frac{5.0611-5}{\frac{0.2803}{\sqrt{42} } }= 1.41

d) The value of the statistic is between the two critical values so the decision is to not reject the null hypothesis. Then using a significance level of 10% there is no significant evidence to reject the null hypothesis so the valve plates have on average tensile strength of 5 lbs/mm.

e) The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis). If the test is two-tailed, so is the p-value, you can calculate it as:

P(Z≤-1.41) + P(Z≥1.41)= P(Z≤-1.41) + (1 - P(Z≤1.41))= 0.079 + ( 1 - 0.921)= 0.158

p-value: 0.158

I hope it helps!

5 0
3 years ago
Other questions:
  • X/3 = -9, plz solve this
    15·2 answers
  • How do you find the product of a fraction then put it in simplest form
    8·2 answers
  • One car rental agency rents a basic car at a daily rate of ​$37.95 plus 40 cents per mile. Another company rents a basic car for
    11·1 answer
  • Please help asap! giving brainliest!
    9·2 answers
  • While resaerching facts on the planet earth kate learned that a true earth day
    5·1 answer
  • ILL GIVE BRAINLIEST I PROMISE HELP ME GOD HELP PLEASE PLEASE I BEG OF YOU PLEASE PELASE PLEASE OH MY GOD
    12·1 answer
  • A boy pushes a bike with 5 newtons up a hill that is 300 meter long. How much work does he do?
    7·1 answer
  • A, B &amp; C form a triangle where ∠ BAC = 90°. AB = 13.5 mm and CA = 3.2 mm. Find the length of BC, giving your answer rounded
    11·1 answer
  • What repeated mathematical operation is represented using exponents?<br>​
    6·1 answer
  • (a+3b)(2c+d+4e) simplify​
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!