Try, pls, this decision (step by step).
Point (5.8;-2;4.2) belongs to the plane and line.
Sin0= y/r
X= -4 and r= 9 (radius is also the hypotenuse)
In quadrant II y is positive
X^2 +y^2 = r^2
-4^2 + y^2 = 9^2
16 + y^2 = 81
Y^2 = 81-16
Y^2 = 65
Y= sqrt65
Sin0= sqrt65/9
When h=0, that is when it hits the ground
0=70-4t-16t²
based on your previous questions, you should have learned how to complete the square
solve by copmleting the square
minus 70 both sides
-70=-4t-16t²
times both sides by -1
70=4t+16t²
16t²+4t=70
divide both sides by 16
t²+1/4t=35/8
take 1/2 of the linear coefint and square it
half of 1/4=1/8, (1/8)²=1/64
add that to both sides
t²+1/4t+1/64=35/8+1/64
factor perfect square trionomial



square root both sides, remember to take positive and negative roots

minus 1/8


or

the 2nd solution is not valid because that gives us a negative time, before the ball was dropped
so

is the solution
t≈1.97
1.97 seconds
Answer:
Answer:
-13
Step-by-step explanation
Rounded to the nearest 0.01 or
the Hundredths Place.
√(75m^3b
Whenever you are looking to simplify a radical, you want to see what the prime factorization of the elements under the radical...
√(3*5*5*m*m*m*b) now you can move out the squared terms (we move out all of the terms that appear twice in this case(
5m√(3mb)