All categories

3 years ago

Step by step to this please

Mathematics

2 answers:

vladimir1956 [14]3 years ago

6 0

Answer:

Step-by-step explanation:

1) Substitute the values of t, v, and w into the expression:

$(-2)^{2} + (1)(3)$

2) Simplify the terms:

$(-2)^{2} + (1)(3)\\=4 + 3\\= 7$

Drupady [299]3 years ago

6 0

Answer:

Step-by-step explanation:

-2^2+3

4+3

You might be interested in

PLEASE HELP I DON'T KNOW I NEVER USED A CALCULATOR WITHOUT A PERCENT PLEASE HELP ME!!!

Snowcat [4.5K]

Answer:

Below

Step-by-step explanation:

% = /100

$\frac{6}{100} \times 40.85$

After you work out the value of the raise add it to the old pay and you get his new pay .

So basically , it's :

$( \frac{6}{100} \times 40.85) + 40.85$

7 0

3 years ago

Read 2 more answers

Use the chain rule to find dw/dt. w = ln x2 + y2 + z2 , x = 7 sin(t), y = 9 cos(t), z = 6 tan(t)

DENIUS [597]

By the chain rule,

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

We have

$\dfrac{\partial w}{\partial x}=\dfrac{2x}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial y}=\dfrac{2y}{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac{2z}{x^2+y^2+z^2}$

$\dfrac{\mathrm dx}{\mathrm dt}=7\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-9\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=6\sec^2t$

So we have

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac2{x^2+y^2+z^2}\left(7x\cos t-9y\sin t+6z\sec^2t\right)$
$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{2\left(49\sin t\cos t-81\cos t\sin t+36\tan t\sec^2t\right)}{49\sin^2t+81\cos^2t+36\tan^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{8\sin t(9-16\cos^4t)}{\cos t(36+13\cos^2t+32\cos^4t)}$

3 0

3 years ago

What does the greater than and less than signs look like

sdas [7]

This: >(Greater than) and <(less than)

6 0

3 years ago

Read 2 more answers

The product of x and y is less than or equal to 4

Trava [24]

Product means multiplication. So the equation would be xy ≤ 4.

3 0