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3 years ago

the side lengths of a triangle are increased by 50% to make a similar triangle. does the area increase by 50% as well?

2 answers:

7 0

The answer is definitely No. For example, if the rectangle is increased by 2, the area must be 4 times. Apply the same to this triangle. Hope it help!

Anarel [89]3 years ago

6 0

No. The new area is 2.25 times the original area. That's (1.5 times 1.5).

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Endpoints of segment MN have coordinates (0, 0), (5, 1). The endpoints of segment AB have coordinates (1 1/22 , 2 1/4 ) and (−2

Nana76 [90]

Answer: $k=18\dfrac{8}{11}$ .

Step-by-step explanation:

If a line passing through two points, then

$Slope=\dfrac{y_2-y_1}{x_2-x_1}$

Endpoints of segment MN have coordinates (0, 0) and (5, 1).

Slope of MN $=\dfrac{1-0}{5-0}=\dfrac{1}{5}$

The endpoints of segment AB have coordinates $\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)$ and $\left(-2\dfrac{1}{4} , k\right)$ .

$A=\left(1\dfrac{1}{22} , 2\dfrac{1}{4}\right)=\left(\dfrac{23}{22} ,\dfrac{9}{4}\right)$

$B=\left(-2\dfrac{1}{4} , k\right)=\left(-\dfrac{9}{4} , k\right)$ .

Slope of AB $=\dfrac{k-\frac{9}{4}}{-\frac{9}{4}-\dfrac{23}{22}}$

$=\dfrac{\frac{4k-9}{4}}{\frac{-99-46}{44}}$

$=\dfrac{4k-9}{4}\times \dfrac{44}{-145}$

$=4k-9\times \dfrac{11}{-145}$

$=\dfrac{44k-99}{-145}$

Product of slopes of two perpendicular segments is -1.

Slope of MN × Slope of AB = -1

$\dfrac{1}{5}\times \dfrac{44k-99}{-145}=-1$

$\dfrac{44k-99}{-725}=-1$

$44k-99=725$

$44k=725+99$

$k=\dfrac{824}{44}$

$k=\dfrac{206}{11}$

$k=18\dfrac{8}{11}$

Therefore, the value of k is $k=18\dfrac{8}{11}$ .

8 0

3 years ago

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HELP meeeeee please

Rufina [12.5K]

Answer: a = 23, b = 21, c = 136

Step-by-step explanation:

8 0

3 years ago

What is the simplest form of 8/40?

ehidna [41]

1/5 is the Simples Form

5 0

3 years ago

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if an external point of a circle is at a distance equal to the diameter of the circle from the center of the circle, the length

jeka57 [31]

Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem

t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).

So t = √(3r^2) = √3r answer.

7 0

3 years ago

Consider a bag containing five red marbles, three green ones, one transparent one, three yellow ones, and three orange ones How

Novay_Z [31]

Answer: 56

Step-by-step explanation:

Given : Number of red marbles = 5

Number of green marbles = 3

Number of yellow marbles = 3

Number of orange marbles = 3

Number of red and green marbles = 5+3=8

Now the possible number of sets (combinations) of five marbles are there in which all of them red or green will be :-

$^8C_5=\dfrac{8!}{5!(8-5)!}=\dfrac{8\times7\times6\times5!}{5!3!}=56$

Hence, the number of sets of five marbles in which all of them red or green=56

4 0

3 years ago