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Zina [86]
4 years ago
7

Explain the connection between earth’s magnetic field and iron

Biology
1 answer:
Mnenie [13.5K]4 years ago
8 0

Answer:

The Earth's magnetic field is somewhat caused by the composition of the earth's core which is rich in iron minerals. There is a solid inner core that is made of iron which makes up to 2/3 of the moon's size. The charged metal of the iron produces electric currents, consequently resulting to Earth's magnetic field.

Explanation:

The Earth's magnetic field is somewhat caused by the composition of the earth's core which is rich in iron minerals. There is a solid inner core that is made of iron which makes up to 2/3 of the moon's size. The charged metal of the iron produces electric currents, consequently resulting to Earth's magnetic field.

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The picture shows a model of a cell what is the main function of the part labeled y in the model
Pavel [41]

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the part that is labeled y helps the plant get water, since plants arent like us they need to have something in their cell to help them get water because they can't just get up and go get a drink like us.

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What determines the color of a rock?
Ivahew [28]

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You are classifying an organism and trying to determine to which domain it belongs. the organism is unicellular and was isolated
EastWind [94]
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4 0
3 years ago
¿Cuántos gramos de dióxido de carbono (CO2) se producen si se quema 40 gramos del hidrocarburo ( C3H8 )?
Valentin [98]

Answer:

120 gramos de CO₂

Explanation:

La ecuación química balanceada para la reacción de combustión del hidrocarburo C₃H₈ (propano) es la siguiente:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

Por lo tanto, 1 mol de C₃H₈ produce 3 moles de CO₂. Ahora debemos convertir las moles a gramos utilizando el peso molecular (PM) de cada compuesto:

PM(C₃H₈)= (3 x 12 g/mol) + (8 x 1 g/mol) = 44 g/mol

1 mol C₃H₈ = 1 mol x 44 g/mol = 44 g

PM(CO₂) = 12 g/mol + (16 g/mol x 2) = 44 g/mol

3 mol CO₂ = 3 mol x 44 g/mol = 132 g

Por lo tanto, se producen 132 gramos de CO₂ a partir de 44 gramos de C₃H₈ y la relación estequiométrica es:

3 mol CO₂/1 mol C₃H₈ = 132 g CO₂/44 g C₃H₈

Finalmente, para calcular cuántos gramos de CO₂ se producen al quemar 40 g de C₃H₈, multiplicamos la relación estequiométrica por la masa a quemar:

masa CO₂ producida = 40 g C₃H₈ x 132 g CO₂/44 g C₃H₈= 120 g

3 0
3 years ago
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