What is the midpoint of (2,-2,4) and (-2,0,6)

1 answer:

6 0

Midpoint of (a,b,c) and (e,f,g) is
((a+e)/2,(b+f)/2,(c+g)/2)
just average them

the x value
(2+-2)/2=0/2=0

the y value
(-2+0)/2=-2/2=-1

the z value
(4+6)/2=10/2=5

(0,-1,5) is da midopint

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ALGEBRA 1, SEMESTER 2

SIZIF [17.4K]

So firstly, we have to find f(x) when x = 8 and x = 0. Plug the two numbers into the x variable of the function to solve for their f(x):

$f(0)=\frac{2*0+3}{3*0-3}\\ f(0)=\frac{0+3}{0-3}\\ f(0)=\frac{3}{-3}\\ f(0)=-1\\ \\ f(8)=\frac{2*8+3}{3*8-3}\\ f(8)=\frac{16+3}{24-3}\\ f(8)=\frac{19}{21}$

Now that we have their y's, we can use the slope, aka average rate of change, formula, which is $\frac{y_2-y_1}{x_2-x_1}$ . Using what we have, we can solve it as such:

$\frac{\frac{19}{21}-(-1)}{8-0}=\frac{\frac{40}{21}}{8}=\frac{40}{21*8}=\frac{40}{168}=\frac{5}{21}$

In short, the average rate of change from x = 0 to x = 8 is 5/21.

8 0

2 years ago

The line segment, AB has a point C as its midpoint. If A is at (2,2) and C is at (5,4) what are the coordinates of the endpoint

Alecsey [184]

Answer:

( 8 , 6 )

Step-by-step explanation:

A = ( 2 , 2 ) and C = ( 5 , 4 )

→ Form an equation

$\frac{2+x}{2} =5$ and $\frac{2+y}{2}=4$

→ Now solve them

2 + x = 10 and 2 + y = 6

→ Simply find the values

x = 8 and y = 6

5 0

2 years ago

Read 2 more answers

If a cot α = 1 and b cos α = 1, find a2 – b 2

S_A_V [24]

The equivalent expression of the different of two square is -1

Given the following expressions

a cot α = 1

a = 1/cot α = sinα/cosα

b = 1/cos α

We are to find the expression a² - b²

According to difference of two squares;

a² - b² = (a + b) (a - b)

Substitute the given expressions into the formula as shown:

$a^2 - b^2 = (\frac{sin \alpha}{cos \alpha} )^2 - (\frac{1}{cos \alpha} )^2\\a^2 - b^2=\frac{sin^2 \alpha}{cos^2 \alpha} -\frac{1}{cos ^2 \alpha}\\a^2 - b^2=\frac{sin^2 \alpha-1}{cos^2\alpha}\\a^2 - b^2=\frac{-(1-sin^2\alpha)}{cos^2\alpha} \\a^2 - b^2=\frac{-os^2 \alpha}{cos^2 \alpha}\\a^2 - b^2 = -1$