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Alexus [3.1K]
3 years ago
5

What is the midpoint of (2,-2,4) and (-2,0,6)

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
6 0
Midpoint of (a,b,c) and (e,f,g) is
((a+e)/2,(b+f)/2,(c+g)/2)
just average them

the x value
(2+-2)/2=0/2=0

the y value
(-2+0)/2=-2/2=-1

the z value
(4+6)/2=10/2=5

(0,-1,5) is da midopint
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gregori [183]

Answer and step-by-step explanation:

For any rectangle, the one with the largest area will be the one whose dimensions are as close to a square as possible.

However, the dividers change the process to find this maximum somewhat.

Letting x represent two sides of the rectangle and the 3 parallel dividers, we have 2x+3x = 5x.

Letting y represent the other two sides of the rectangle, we have 2y.

We know that 2y + 5x = 750.

Solving for y, we first subtract 5x from each side:

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Next we divide both sides by 2:

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y = -2.5x + 375

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A = xy

Substituting the expression for y we just found above, we have

A = x(-2.5x+375)

A = -2.5x² + 375x

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x = -375/2(-2.5) = -375/-5 = 75

Substituting this back in place of every x in our area equation, we have

A = -2.5x² + 375x

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