1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lunna [17]
3 years ago
9

CAN SOMEONE PLEASE SHOW WORK FOR THESE PROBLEMS WILL GIVE BAINLIEST!!!!!!!!!EMERGENCY

Mathematics
1 answer:
azamat3 years ago
5 0

Answer:

Part 1) x\geq10

Part 2) m\leq -9  

Part 3) p\geq 5

Part 4) x  

Part 5) b

Part 6)   n

Part 7)  n

Part 8) r\leq 4

Part 9) x\geq 7

Part 10) p\leq 0

Part 11) x

Part 12) a > 24

Step-by-step explanation:

Part 1) 2x+4\geq24  

Subtract 4 both sides

2x\geq24-4

2x\geq20

Divide by 2 both sides

x\geq10

the solution is the interval ------> [10,∞)

The solution is the shaded area to the right of the solid line at number 10 (closed circle).

see the attached figure  

Part 2) \frac{m}{3}-3\leq -6  

Adds 3 both sides

\frac{m}{3}\leq -6+3  

\frac{m}{3}\leq -3  

Multiply by 3 both sides

m\leq -9  

the solution is the interval ------> (-∞,-9]

The solution is the shaded area to the left of the solid line at number -9 (closed circle).

see the attached figure  

Part 3) -3(p+1)\leq -18  

applying the distributive property left side

-3p-3\leq -18  

adds 3 both sides

-3p\leq -18+3  

-3p\leq -15  

Multiply by -1 both sides

3p\geq 15

Divide by 3 both sides

p\geq 5

the solution is the interval ------> [5,∞)

The solution is the shaded area to the right of the solid line at number 5 (closed circle).

see the attached figure

Part 4) -4(-4+x)>56  

applying the distributive property left side  

16-4x>56  

Subtract 16 both sides  

-4x>56-16  

-4x>40  

Multiply by -1 both sides

4x  

Divide by 4 both sides

x  

the solution is the interval ------> (-∞,-10)

The solution is the shaded area to the left of the dashed line at number -10 (open circle).

see the attached figure

Part 5) -b-2>8

adds 2 both sides

-b>8+2

-b>10

Multiply by -1 both sides

b

the solution is the interval ------> (-∞,-10)

The solution is the shaded area to the left of the dashed line at number -10 (open circle).

Part 6) -4(3+n)>-32

applying the distributive property left side  

-12-4n>-32

adds 12 both sides

-4n>-32+12

-4n>-20

multiply by -1 both sides

4n

divide by 4 both sides

n

the solution is the interval ------> (-∞,5)

The solution is the shaded area to the left of the dashed line at number 5 (open circle).

see the attached figure

Part 7) 4+\frac{n}{3}

Subtract 4 both sides

\frac{n}{3}

\frac{n}{3}

Multiply by 3 both sides

n

the solution is the interval ------> (-∞,6)

The solution is the shaded area to the left of the dashed line at number 6 (open circle).

see the attached figure  

Part 8) -3(r-4)\geq 0

applying the distributive property left side

-3r+12\geq 0

subtract 12 both sides

-3r\geq -12    

divide by -1 both sides

3r\leq 12

divide by 3 both sides

r\leq 4

the solution is the interval ------> (-∞,4]

The solution is the shaded area to the left of the solid line at number 4 (closed circle).

see the attached figure  

Part 9) -7x-7\leq -56  

Adds 7 both sides

-7x\leq -56+7

-7x\leq -49

Multiply by -1 both sides

7x\geq 49

Divide by 7 both sides

x\geq 7  

the solution is the interval ------> [7,∞)

The solution is the shaded area to the right of the solid line at number 7 (closed circle).

see the attached figure  

Part 10) -3(p-7)\geq 21  

applying the distributive property left side

-3p+21\geq 21  

subtract 21 both sides

-3p\geq 21-21  

-3p\geq 0  

Multiply by -1 both sides

3p\leq 0

p\leq 0

the solution is the interval ------> (-∞,0]

The solution is the shaded area to the left of the solid line at number 0 (closed circle).

see the attached figure  

Part 11)  -11x-4> -15

Adds 4 both sides

-11x> -15+4

-11x> -11

Multiply by -1 both sides

11x

Divide by 11 both sides

x

the solution is the interval ------> (-∞,1)

The solution is the shaded area to the left of the dashed line at number 1 (open circle).

see the attached figure

Part 12) \frac{-9+a}{15}>1  

Multiply by 15 both sides

-9+a > 15

Adds 9 both sides

a > 15+9

a > 24

the solution is the interval ------> (24,∞)

The solution is the shaded area to the right of the dashed line at number 24 (open circle).

see the attached figure

You might be interested in
Picture attached below<br><br> A. 1/2<br> B. √3/3<br> C. √2/2<br> D. 1
Olenka [21]

Answer:

Point B is the answer......

6 0
3 years ago
Read 2 more answers
A box of cereal has 11 servings and has a total of 77 grams of fiber. Find the unit rate of grams of fiber per serving.
Ksenya-84 [330]
77 g of fiber/ 11 servings= 7 g of fiber/ 1 serving.

The final answer is 7 g of fiber/serving~
7 0
3 years ago
Mark was thinking of a number. Mark subtracts 6.2 from the number and gets an answer of 68. Form an equation with
oksano4ka [1.4K]

Answer:

X= 6.2 + 68 ???

Step-by-step explanation:

I'm not sure that's what I would write in an exam

7 0
3 years ago
The harmonic motion of a particle is given by f(t) = 2 cos(3t) + 3 sin(2t), 0 ≤ t ≤ 8. (a) When is the position function decreas
iren [92.7K]

For the last part, you have to find where f'(t) attains its maximum over 0\le t\le8. We have

f'(t)=-6\sin3t+6\cos2t

so that

f''(t)=-18\cos3t-12\sin2t

with critical points at t such that

-18\cos3t-12\sin2t=0

3\cos3t+2\sin2t=0

3(\cos^3t-3\cos t\sin^2t)+4\sin t\cos t=0

\cos t(3\cos^2t-9\sin^2t+4\sin t)=0

\cos t(12\sin^2t-4\sin t-3)=0

So either

\cos t=0\implies t=\dfrac{(2n+1)\pi}2

or

12\sin^2t-4\sin t-3=0\implies\sin t=\dfrac{1\pm\sqrt{10}}6\implies t=\sin^{-1}\dfrac{1\pm\sqrt{10}}6+2n\pi

where n is any integer. We get 8 solutions over the given interval with n=0,1,2 from the first set of solutions, n=0,1 from the set of solutions where \sin t=\dfrac{1+\sqrt{10}}6, and n=1 from the set of solutions where \sin t=\dfrac{1-\sqrt{10}}6. They are approximately

\dfrac\pi2\approx2

\dfrac{3\pi}2\approx5

\dfrac{5\pi}2\approx8

\sin^{-1}\dfrac{1+\sqrt{10}}6\approx1

2\pi+\sin^{-1}\dfrac{1+\sqrt{10}}6\approx7

2\pi+\sin^{-1}\dfrac{1-\sqrt{10}}6\approx6

4 0
3 years ago
What is the reciprocal of -11/30 in a fraction
VMariaS [17]

Answer:

30/-11

Step-by-step explanation:

u just have to flip it good luck : )

7 0
3 years ago
Read 2 more answers
Other questions:
  • Please help. will mark brainliest if its right.180-x=3(90-x)
    5·1 answer
  • Please help me thanks
    8·1 answer
  • Write an algebraic expression for the word phrase. the product of 8 and s.
    15·1 answer
  • The area of arizona covered by desert is about 5880 square miles.if 42% of the total area is desert , about how many square mile
    15·1 answer
  • 1) While your family is visiting Deep Creek Lake, you and your brother decide to go boating. The
    5·1 answer
  • Help Me! ASAP! Which of the follow statements is NOT true?​
    6·2 answers
  • Two different formulas of an oxygenated motor fuel are being tested to study their road octane numbers. The variance of road oct
    10·1 answer
  • I want to know what the answer to this question is.
    5·2 answers
  • Please help with this
    5·1 answer
  • Someone please help me on this and actually answer I’m so confused and need help lots of points
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!