Answer:
Part 1)
Part 2)
Part 3)
Part 4)
Part 5)
Part 6)
Part 7)
Part 8)
Part 9)
Part 10)
Part 11)
Part 12)
Step-by-step explanation:
Part 1)
Subtract 4 both sides
Divide by 2 both sides
the solution is the interval ------> [10,∞)
The solution is the shaded area to the right of the solid line at number 10 (closed circle).
see the attached figure
Part 2)
Adds 3 both sides
Multiply by 3 both sides
the solution is the interval ------> (-∞,-9]
The solution is the shaded area to the left of the solid line at number -9 (closed circle).
see the attached figure
Part 3)
applying the distributive property left side
adds 3 both sides
Multiply by -1 both sides
Divide by 3 both sides
the solution is the interval ------> [5,∞)
The solution is the shaded area to the right of the solid line at number 5 (closed circle).
see the attached figure
Part 4)
applying the distributive property left side
Subtract 16 both sides
Multiply by -1 both sides
Divide by 4 both sides
the solution is the interval ------> (-∞,-10)
The solution is the shaded area to the left of the dashed line at number -10 (open circle).
see the attached figure
Part 5)
adds 2 both sides
Multiply by -1 both sides
the solution is the interval ------> (-∞,-10)
The solution is the shaded area to the left of the dashed line at number -10 (open circle).
Part 6)
applying the distributive property left side
adds 12 both sides
multiply by -1 both sides
divide by 4 both sides
the solution is the interval ------> (-∞,5)
The solution is the shaded area to the left of the dashed line at number 5 (open circle).
see the attached figure
Part 7)
Subtract 4 both sides
Multiply by 3 both sides
the solution is the interval ------> (-∞,6)
The solution is the shaded area to the left of the dashed line at number 6 (open circle).
see the attached figure
Part 8)
applying the distributive property left side
subtract 12 both sides
divide by -1 both sides
divide by 3 both sides
the solution is the interval ------> (-∞,4]
The solution is the shaded area to the left of the solid line at number 4 (closed circle).
see the attached figure
Part 9)
Adds 7 both sides
Multiply by -1 both sides
Divide by 7 both sides
the solution is the interval ------> [7,∞)
The solution is the shaded area to the right of the solid line at number 7 (closed circle).
see the attached figure
Part 10)
applying the distributive property left side
subtract 21 both sides
Multiply by -1 both sides
the solution is the interval ------> (-∞,0]
The solution is the shaded area to the left of the solid line at number 0 (closed circle).
see the attached figure
Part 11)
Adds 4 both sides
Multiply by -1 both sides
Divide by 11 both sides
the solution is the interval ------> (-∞,1)
The solution is the shaded area to the left of the dashed line at number 1 (open circle).
see the attached figure
Part 12)
Multiply by 15 both sides
Adds 9 both sides
the solution is the interval ------> (24,∞)
The solution is the shaded area to the right of the dashed line at number 24 (open circle).
see the attached figure