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3 years ago

Please help me asap! Thanks in advanced guys! :)

Mathematics

2 answers:

sp2606 [1]3 years ago

6 0

Answer:

x = 17 because 8x + 20 equals 11x-31, you simplify both by subtrcting 8x from both sides to get 20 = 3x -31. Then you add 31 to both sides to get 51 = 3x. Then divide 3 from both sides and you get 17 = x

cluponka [151]3 years ago

5 0

Answer:

I think I did it wrong but I try

Step-by-step explanation:

8x+20+11x-31

-8x -8x

20-31 =3x

+31 +31

51 =3x

17=x

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What is 1/4 ➗ 9 in simplest form? and how do i simplify it?

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Answer:

1/36

Step-by-step explanation:

1/4 ÷ 9

= 1/4 x 1/9

= 1/36

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3 years ago

Help! I need help. My teacher made it an anime one. If todoroki had 7 ’s how much will he get when he has 67352 if you needed to

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3 years ago

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HELLPPP PLSSS<br><br>100÷10+3-100+ (6+ 19)+ 3 × -5 -19+100

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Answer:

Step-by-step explanation:

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3 0

3 years ago

The difference between the two roots of the equation 3x^2+10x+c=0 is 4 2/3 . Find the solutions for the equation.

andrezito [222]

Answer:

Given the equation: $3x^2+10x+c =0$

A quadratic equation is in the form: $ax^2+bx+c = 0$ where a, b ,c are the coefficient and a≠0 then the solution is given by :

$x_{1,2} = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$ ......[1]

On comparing with given equation we get;

a =3 , b = 10

then, substitute these in equation [1] to solve for c;

$x_{1,2} = \frac{-10\pm \sqrt{10^2-4\cdot 3 \cdot c}}{2 \cdot 3}$

Simplify:

$x_{1,2} = \frac{-10\pm \sqrt{100- 12c}}{6}$

Also, it is given that the difference of two roots of the given equation is $4\frac{2}{3} = \frac{14}{3}$

i.e,

$x_1 -x_2 = \frac{14}{3}$

Here,

$x_1 = \frac{-10 + \sqrt{100- 12c}}{6}$ , ......[2]

$x_2= \frac{-10 - \sqrt{100- 12c}}{6}$ .....[3]

then;

$\frac{-10 + \sqrt{100- 12c}}{6} - (\frac{-10 + \sqrt{100- 12c}}{6}) = \frac{14}{3}$

simplify:

$\frac{2 \sqrt{100- 12c} }{6} = \frac{14}{3}$

$\sqrt{100- 12c} = 14$

Squaring both sides we get;

$100-12c = 196$

Subtract 100 from both sides, we get

$100-12c -100= 196-100$

Simplify:

-12c = -96

Divide both sides by -12 we get;

c = 8

Substitute the value of c in equation [2] and [3]; to solve $x_1 , x_2$

$x_1 = \frac{-10 + \sqrt{100- 12\cdot 8}}{6}$

$x_1 = \frac{-10 + \sqrt{100- 96}}{6}$ or

$x_1 = \frac{-10 + \sqrt{4}}{6}$

Simplify:

$x_1 = \frac{-4}{3}$

Now, to solve for $x_2$ ;

$x_2 = \frac{-10 - \sqrt{100- 12\cdot 8}}{6}$

$x_2 = \frac{-10 - \sqrt{100- 96}}{6}$ or

$x_2 = \frac{-10 - \sqrt{4}}{6}$

Simplify:

$x_2 = -2$

therefore, the solution for the given equation is: $-\frac{4}{3}$ and -2.

3 0

3 years ago

Suppose you know that Mr. and Mrs. Vincent have at most eight children. One day you happen to meet two girls who were the Vincen

lianna [129]

Answer:

The number of children are 4 out of which 3 are girls

Step-by-step explanation:

Data provided in the question:

P(Two randomly selected children are girls) = $\frac{1}{2}$

now,

let the number of children be 'n'

the number of girls be 'x'

thus,

P(Two randomly selected children are girls) = $\frac{^xC_2}{^nC_2}$ = $\frac{1}{2}$

also,

$^nC_r$ = $\frac{n!r!}{(n-r)!}$

thus,

$\frac{\frac{x!2!}{(x-2)!}}{\frac{n!2!}{(n-2)!}}$ = $\frac{1}{2}$

$\frac{x(x-1)}{n(n-1)}$ = $\frac{1}{2}$

2x(x-1) = n(n-1)

now

for x = 3 and n = 4

i.e

2(3)(3-1) = 4(4-1)

12 = 12

hence, the relation is justified

therefore,

The number of children are 4 out of which 3 are girls

3 0

3 years ago