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Define x :
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Let one of the number be x. The other number is x + 2.
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Construction Equation :
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The sum of the square of the two number is 202.
![x^2 + (x+2)^2 = 202](https://tex.z-dn.net/?f=x%5E2%20%2B%20%28x%2B2%29%5E2%20%3D%20202)
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Solve for x :
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![x^2 + (x+2)^2 = 202](https://tex.z-dn.net/?f=x%5E2%20%2B%20%28x%2B2%29%5E2%20%3D%20202)
![x^2 + x^2 + 4x + 4 = 202](https://tex.z-dn.net/?f=x%5E2%20%2B%20x%5E2%20%2B%204x%20%2B%204%20%3D%20202)
![2x^2 + 4x - 198 = 0](https://tex.z-dn.net/?f=2x%5E2%20%2B%204x%20-%20198%20%3D%200)
![x^2 + 2x - 99 = 0](https://tex.z-dn.net/?f=x%5E2%20%2B%202x%20-%2099%20%3D%200)
![(x+11)(x-9) =0](https://tex.z-dn.net/?f=%20%28x%2B11%29%28x-9%29%20%3D0)
![(x+11)= 0 \ \ or \ \ (x-9) =0](https://tex.z-dn.net/?f=%20%28x%2B11%29%3D%200%20%5C%20%5C%20or%20%5C%20%5C%20%28x-9%29%20%3D0)
![x = - 11 \ or \ x = 9](https://tex.z-dn.net/?f=x%20%3D%20-%2011%20%5C%20or%20%5C%20%20x%20%3D%209%20)
x = -11 is rejected, since it only want positive integer.
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Find the two numbers :
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x = 9.
x + 3 = 11
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Answer: The numbers are 9 and 11.----------------------------------------------------------
6sqrt6 (~14.7)
~5.5
~12.2
~13.4
~14.7
**THIS (~) MEANS THAT IT IS ROUNDED TO THE TENTH
Answer:
y= -5x=5
Step-by-step explanation:
m=y-y/x-x
(1,0) (0,5)
m=0-5/1-0
m= -5
y= -5x+5