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2 years ago

For the given matrix a find a 3 x 2 nonzero matrix b such that

Mathematics

1 answer:

Arlecino [84]2 years ago

5 0

Your question is incomplete sir

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PLEASE HELP! ! ! urgent!

sertanlavr [38]

Answer:

$6(\frac{1}{3} \times\frac{7}{5} )=(6\times\frac{1}{3} )\frac{7}{5}$

$Answer: B$

Hope it helps...

Have a great day!!

8 0

3 years ago

8. A skateboard ramp is 5ft tall and is 12ft from the base of the ramp to the end. What is the length from the top of the ramp t

Elden [556K]

Answer:

iacbsc kakwc s s k kd sdidv d lm vdfj

Step-by-step explanation:

7 0

2 years ago

Brainlyst for best answer with work shown

wlad13 [49]

Answer:

5*5 = one face = 25 inches squared

6 faces times 25 inches square = 150 inches squared

Step-by-step explanation:

4 0

2 years ago

Solve the rational equation 1/n-4 - 2/n = 3/4-n

Leokris [45]

Answer:

n=4

Step-by-step explanation:

Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]

Simplifying the Left Hand Side of the equation by taking the LCM of the denominator terms:

\[\frac{n}{n*(n-4)}-\frac{2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2n + 8}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{8 - n}{n*(n-4)}=\frac{3}{4-n}\]

=> \[(8-n)*(4-n) =n*(n-4)*3\]

=> \[n-8 =3n\]

=> \[2n =8\]

=> n = 4

5 0

3 years ago

There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is

shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, $n(P) = 6$

Number of orange socks, $n(O) = 4$

Two socks are picked without replacement.

Now, total number of socks, $n(T)=N(P)+n(O)=6+4=10$

Probability of picking the first cap as purple cap is given as:

$P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}$

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

$P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}$

Now, probability that both the picked caps are purple is given by their probability product. This gives,

$P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33$

Therefore, the probability that he picked 2 purpled socks is 0.33

4 0

3 years ago