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Tom [10]
3 years ago
6

Lucinda is writing a coordinate proof to show that a diagonal of a parallelogram partitions the parallelogram into two equal are

as.

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
6 0

Answer:

did you ever find the answer?

Step-by-step explanation:

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What is the system of inequalities associated with the following graph?
slamgirl [31]

One line passes through the points (-2,3) and (0,-3) , it means the y intercept is b=-3

and slope m = \frac{(-3-3)}{0-(-2)}

= \frac{-6}{2}= -3

So the equation of line will be y= -3x -3

And the inequality should be y\geq -3x-3

Or 3x +y \geq -3

And the other line passes through (-2,3) and (0,2)

So the y intercept is b=2

and the slope is m= \frac{2-3}{0-(-2)} = \frac{-1}{2}

So the equation of line will be y= \frac{-1}{2} x +2\\and the inequality should be  y \leq \frac{-1}{2} x+2

Or

2y +x \leq 4

So answer is 3x +y \geq -3,  x+2y\leq 4

6 0
3 years ago
Read 2 more answers
HELP I WILL MARK YOU BRAINLIEST!! IT DOESN’T GIVE ME THE OPTION UNTIL TWO PEOPLE HAVE ANSWERED
TEA [102]

Answer:

B. Same distance and same direction

Step-by-step explanation:

The points have to move together while maintaining the same shape.

3 0
2 years ago
Show 46/200 on the hundredths grid. then write the fractions as a demical
SSSSS [86.1K]
If we want to has 100 in the denominator we have to divide numerator and denominator by 2. Then total value of fraction doesnt change.
\frac{46}{200}= \frac{46:2}{200:2}= \frac{23}{100}
Now read the fraction, its 23 hundreds, now just write as decimal, so, 0.23
3 0
3 years ago
Which expression is equivalent to −10+(−40)+(−90) ?
Igoryamba
The answer is D because -10+(-40)+(-90) is the same just swiched
8 0
3 years ago
Read 3 more answers
If -2x +7 = 3x - 8, then x =
Anna11 [10]
-2x +7 = 3x - 8

Move the variable to the left-hand side and change its sign

-2x -3x+ 7 = -8

Move the constant to the right-hand side and change its sign

-2x -3x = -8 -7

Collect like terms

-5x = -15

Divide both sides of the equation by -5

x=3
6 0
3 years ago
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