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finlep [7]
3 years ago
8

Factor. 4m6−16p10 (2m3−4p5)(2m3+4p5) (2m3−4p5)2 (2m3−4p5)(2m3−4p5) (2m3+4p5)2

Mathematics
2 answers:
sesenic [268]3 years ago
6 0
I think the answer is
8(3m-80p×(6m-20p)^3×(6m+20p)^2)
Ulleksa [173]3 years ago
6 0

Answer:

\text{The factored form is }(2m^3-4p^5)(2m^3+4p^5)

Step-by-step explanation:

\text{Given the expression }4m^6−16p^{10}

we have to factor the above expression.

4m^6-16p^{10}

(2m^3)^2-(4p^5)^2

Using the identity

a^2-b^2=(a-b)(a+b)

\text{Put }a=2m^3, b=4p^5

(2m^3)^2-(4p^5)^2=(2m^3-4p^5)(2m^3+4p^5)

which is required factored form.

Option 1 is correct.

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Simplify the expression, Please help!!
Serhud [2]
For the first one it would be C.
3 0
3 years ago
Could someone solve this for me.
Studentka2010 [4]
The answer is 7.6 units
5 0
3 years ago
WILL MARK BRAINLIEST FEELING LAZY WORTH 15 POINTS
Zinaida [17]

The irrational numbers are: √8, √10 and √15

Step-by-step explanation:

A rational number is a number that can be written in the form p/q where p&q are integers and q≠0.

"All the numbers whose square root is not a whole number and has an infinite number of digits after decimal, are irrational numbers"

So in the given options

\sqrt{4} = 2

Which can be written in the required form so √4 is a rational number

\sqrt{8}=2.828427124746190097603.....

√8 has an infinite expansion hence it cannot be written in the p/q form, so it is an irrational number

\sqrt{10}=3.16227766016837933....

√10 has an infinite expansion hence it cannot be written in the p/q form, so it is an irrational number

\sqrt{15}=3.87298334620.....

√15 has an infinite expansion hence it cannot be written in the p/q form, so it is an irrational number

\sqrt{36} = 6

Which can be written in the required form so √36 is a rational number

Hence,

The irrational numbers are: √8, √10 and √15

Keywords: Rational numbers, Irrational numbers

Learn more about rational numbers at:

  • brainly.com/question/3375830
  • brainly.com/question/3398261

#LearnwithBrainly

4 0
4 years ago
Which is a factor of 2x^2y^4-10x2y+14y3-70
VARVARA [1.3K]
2x^2y(y^3-5)+14(y^3-5)
(2x^2y)+14(y^3-5)
2(x^2y+7)(y^3-5)
x^2y+7 Is a factor
3 0
3 years ago
If 2x² – 2y = 125 and x - y = 2.5, find the value of<br> x + y
uysha [10]

We can solve this using substitution.

because x-y=2.5

x=y+2.5

Now substitute x into other equation.

2(y+2.5)^2-2y=125

2y^2+10y+12.5-2y=125

2y^2+8y-112.5=0

Now comes the ugly part

y=-4+-sqrt(16+900)

y=-4+-sqrt916

y=-4+-2sqrt229

x=-1.5+-2sqrt229

6 0
3 years ago
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