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julia-pushkina [17]
3 years ago
10

Which represents the area of ABC ?

Mathematics
2 answers:
disa [49]3 years ago
5 0

A = \frac{1}{2} bc(sin A)

ICE Princess25 [194]3 years ago
5 0

Answer:

A) 1/2(bc sinA)

Step-by-step explanation:

the area of ABC is : 1/2 (h ×AC)

but : AC = b

sinA = h/c    so : h = c sinA

the area of ABC is : 1/2 (c sinA×b ) = 1/2(bc sinA)


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On a particular day, 112 of 280 passengers on a particular DTW-LAX flight used the e-ticket check-in kiosk to obtain boarding pa
Sonja [21]

Answer:

0.2348 = 23.48% probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

Step-by-step explanation:

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Population of 280, which means that N = 280

112 use e-ticket check-in kiosk, which means that k = 112

Sample of eight passengers means that n = 8

Find the approximate hypergeometric probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

This is P(X = 4). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 4) = h(4,280,8,112) = \frac{C_{112,4}*C_{168,4}}{C_{280,4}} = 0.2348

0.2348 = 23.48% probability that four will have used the e-ticket check-in kiosk to obtain boarding passes.

3 0
3 years ago
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