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andriy [413]
3 years ago
8

6.10.1: Modify a C string parameter. Complete the function to replace any period by an exclamation point. Ex: "Hello. I'm Miley.

Nice to meet you." becomes: "Hello! I'm Miley! Nice to meet you!"
Computers and Technology
1 answer:
Andrej [43]3 years ago
6 0

Answer:

#include <iostream>

#include <cstring>

using namespace std;

void replacePeriod(char* phrase) {

int i = 0;

while(*(phrase + i) != '\0')

{

if(*(phrase + i) == '.')

*(phrase + i) = '!';

i++;

}

}

int main() {

const int STRING_SIZE = 50;

char sentence[STRING_SIZE];

strcpy(sentence, "Hello. I'm Miley. Nice to meet you.");

replacePeriod(sentence);

cout << "Updated sentence: " << endl;

cout << sentence << endl;

return 0;

}

Explanation:

  • Create a function called replacePeriod that takes a pointer of type char as a parameter.
  • Loop through the end of phrase, check if phrase has a period and then replace it with a sign of exclamation.
  • Inside the main function, define the sentence and pass it as an argument to the replacePeriod function.
  • Finally display the updated sentence.
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Answer:

Here is the JAVA program:

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   double amount = input.nextDouble();  //scans and reads the value of amount from user

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   int dimes = change / 10;  //  computes dimes

   change = change % 10;  //  computes dimes remaining

   int nickels = change / 5;  // computes nickels

   change = change % 5;  // compute nickels remaining

   int pennies = change;  // computes pennies

   System.out.println("Quarters: " + quarters);  // displays computed value of quarters

   System.out.println("Dimes: " + dimes);  // displays value of dimes

   System.out.println("Nickels: " + nickels);  // displays value of nickels

   System.out.println("Pennies: " + pennies);   }} //displays value of pennies

Explanation:

I will explain the program with an examples.

Suppose the user enters 4.57 as cost of the item and 5.00 as amount paid. Then the program works as follows:

Change is computed as

change = (int)(amount * 100 - itemCost * 100);

This becomes;

change = (int)(5.00 * 100 - 4.57 * 100)

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change = 43

Now the change owed is computed as:

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Hence change owed = 0.43

Next quarters are computed as:

quarters = change / 25;

This becomes:

quarters = 43/25

quarters = 1

Now the remaining is computed as:

   change = change % 25;

This becomes:

   change = 43 % 25;

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Next the dimes are computed from remaining value of change as:

dimes = change / 10;

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Now the remaining is computed as:

   change = change % 10;

This becomes:

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nickels = 1

Now the remaining is computed as:

   change = change % 5;

This becomes:

   change = 8 % 5

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At last the pennies are computed as:

pennies = change;

pennies = 3

So the output of the entire program is:

Change Owed: 0.43                                                                                                                Quarters: 1                                                                                                                      Dimes: 1                                                                                                                         Nickels: 1                                                                                                                       Pennies: 3  

The screenshot of the output is attached.

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