Answer:
PRINT "Values for Principal (P), Rate (A) and Time (T)"
INPUT P, A, T
I = P * A * T/100
Amount = P + I
PRINT "Interest: ", I
PRINT "Amount: ", Amount
Explanation:
This prompts the user for values for Principal, Rate and Time
PRINT "Values for Principal (P), Rate (A) and Time (T)"
This gets values for Principal (P), Rate (R) and Time (T)
INPUT P, A, T
This calculates the interest (I)
I = P * A * T/100
This calculates the amount (A)
Amount = P + I
This prints the interest (I)
PRINT "Interest: ", I
This prints the amount (A)
PRINT "Amount: ", Amount
Answer:
The answer to this question is given below in the explanation section.
Explanation:
This program is written in C++.
#include <iostream>
using namespace std;
int main()
{
string word;// variable for taking user input
int cond;// to set condition true if user preses the stop and exit from loop
cout<<"Enter word: \n";
cin>>word;
do// start while loop
{
if(word=="stop" || word =="STOP" || word == "Stop")// if user enter word stop, then program exit
{
cond=0;
}
else//otherwise loop continue
{
cout<<" You Entered "+ word +"\n";
cout<<"Enter word: \n";
cin>>word;
cond=1;
}
}
while(cond == 1);// if user don't enter word "stop" loop run continuesly.
cout<<"Program exit";
return 0;
}
Answer:
static int checkSymbol(char ch)
{
switch (ch)
{
case '+':
case '-':
return 1;
case '*':
case '/':
return 2;
case '^':
return 3;
}
return -1;
}
static String convertInfixToPostfix(String expression)
{
String calculation = new String("");
Stack<Character> operands = new Stack<>();
Stack<Character> operators = new Stack<>();
for (int i = 0; i<expression.length(); ++i)
{
char c = expression.charAt(i);
if (Character.isLetterOrDigit(c))
operands.push(c);
else if (c == '(')
operators.push(c);
else if (c == ')')
{
while (!operators.isEmpty() && operators.peek() != '(')
operands.push(operators.pop());
if (!operators.isEmpty() && operators.peek() != '(')
return NULL;
else
operators.pop();
}
else
{
while (!operators.isEmpty() && checkSymbol(c) <= checkSymbol(operators.peek()))
operands.push(operators.pop());
operators.push(c);
}
}
while (!operators.isEmpty())
operands.push(operators.pop());
while (!operands.isEmpty())
calculation+=operands.pop();
calculation=calculation.reverse();
return calculation;
}
Explanation:
- Create the checkSymbol function to see what symbol is being passed to the stack.
- Create the convertInfixToPostfix function that keeps track of the operands and the operators stack.
- Use conditional statements to check whether the character being passed is a letter, digit, symbol or a bracket.
- While the operators is not empty, keep pushing the character to the operators stack.
- At last reverse and return the calculation which has all the results.
There are inhabited areas INSIDE the Amazon Rainforest. Many primitive tribes with little to no contact of the outside world live in remote areas of the rainforest, but the closest major city to the rainforest (also inside) is Manaus, Brazil.
Answer: technician B
Explanation:
The oil is picked up from the oil pump though a pick up tube that is mounted on the oil pump. The end of the pick up tube sits in the oil at the bottom of the oil pan. The oil is then forced through holes that are drilled into the block. Those holes which are called (journals) lead to the main bearings,rod bearings,lifters, camshaft, ect..
