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UNO [17]
3 years ago
6

Help with all 3 please hurry

Mathematics
2 answers:
Anna11 [10]3 years ago
7 0
3 is distribute cause u need to multiply it
abruzzese [7]3 years ago
6 0
3. Commuinitive proterty 4. 0 5. The second one
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Find the slope of the line passing through the given points (-5, 14) and (-1,2).
dexar [7]
So your formula is y1 - y2 divided by x1 - x2. Start off with the -5, 14 as your x1 and y1 because its the biggest out of the other one. So do 14 - 2 = 12 so thats your top part and -5 - -1 which is -4 so your fraction will be 12/-4 or you have -3 as a whole number
6 0
3 years ago
TRUE or FALSE. In a randomly generated list of numbers from 0 to 5, the chance that each number can occur is 1/5 .
mel-nik [20]
Thank you for posting your question here at brainly. Feel free to ask more questions.  

<span>The best and most correct answer among the choices provided by the question is FALSE.</span><span>       
    </span><span>
<span>Hope my answer would be a great help for you.</span></span>
3 0
3 years ago
Read 2 more answers
If X - A = B, what is X?
sineoko [7]

Answer:

x=a+b

Step-by-step explanation:

Just move a to the other side (by adding it)

6 0
3 years ago
Read 2 more answers
14 = 6x4+b <br><br> I WILL MARK BRAINLYIEST FOR 1ST PERSON
Ira Lisetskai [31]
14 = 6x4 + b
14 = 24 + b
-10 = b

Hope this is accurate & helpful! Let me know if there are any errors or if you have any additional questions.
7 0
2 years ago
A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
kkurt [141]

Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

2b^2+4bh=36

b^2+2bh=18

2bh=18-b^2

h=\frac{18-b^2}{2b}

Volume of box, V=b^2h

Substitute the values

V=b^2\times \frac{18-b^2}{2b}

V=\frac{1}{2}(18b-b^3)

Differentiate w. r.t b

\frac{dV}{db}=\frac{1}{2}(18-3b^2)

\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

\implies 3b^2=18

b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}

h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

7 0
3 years ago
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