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s2008m [1.1K]
3 years ago
6

Question 7 of 10

SAT
1 answer:
Alika [10]3 years ago
5 0
The Answer is: C. 1.0
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Notices for files:
azamat

Answer:

Umm Okay

Explanation:

5 0
3 years ago
A probe orbiting venus exerts a gravitational force of 2. 58 × 103 n on venus. Venus has a mass of 4. 87 × 1024 kg. The mass of
Margarita [4]

Answer:

\mathrm{9.08 \times 10^6 \:km}

Explanation:

To solve for the distance between the probe and  the center of Venus, use the formula:

\mathrm{F = \frac{G\: m1 \:m2}{r^2}}

 

<u>Plugin the values</u>:

G =

6.67\times10^{-11} \mathrm{\frac{m3}{kg\: s2}}

\mathrm{F} =2.58 \times 10^3\mathrm{N}

\mathrm{m1 = 4.87 \times 10^{24}\:kg}

\mathrm{m2 = 655\: kg}

Hence:

\mathrm{F = \frac{G\: m1 \:m2}{r^2}}

2.58  \times 10^{23} = 6.67 \times 10^{-11} (4.87 \times 10^{24})

\frac{(655)}{r^2}

\mathrm{r = 9.08 \times 10^6 \:km}

7 0
2 years ago
A 8-acre piece of land is subdivided into 4/7-acre lots. How many lots are there?
Katen [24]
14.

8 / (4/7) = 14 lots
3 0
3 years ago
During last year's basketball season, Jackson attempted
OLga [1]

This question is incomplete and not well written.

Complete question:

During last year's basketball season, Jackson attempted

150 free throws of which he made

120. So far this season, he's attempted 24 and made 16. A player's free-throw percentage is defined to be the percent of free-throws made out of the number of free-throws attempted. Assuming calculations began with the start of last year's season, which of the following best approximates Jackson's overall free-throw percentage to date?

A. 67%

B. 73%

C. 78%

D. 80%

Answer:

B. 73%

Explanation:

In the question, we are told that:

A player's free-throw percentage is defined to be the percent of free-throws made out of the number of free-throws attempted

Mathematically

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted)× 100

For Last year, Jackson attempted

150 free throws of which he made

120

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

Percent(%) Free throw = (120÷150) × 100

= 80%

This season, he's attempted 24 and made 16

Percent (% ) Free throw = (Number if free throws made ÷ Number of free throws attempted) × 100

Percent(%) Free throw = (16÷24) × 100

= 66.67%

Approximately = 67%

The best approximation for Jackson's overall free-throw percentage to date is

(Percent Free Throw for last season + Percent Free Throw for this season) ÷ 2

Percent Free Throw for last season

= 80%

Percent Free Throw for this season = 66.67%

Therefore, (80% + 66.67%) ÷ 2

= 146.67% ÷ 2

= 73.335%

Approximately = 73%

Therefore, Jackson's overall free-throw percentage to date is 73%

6 0
3 years ago
Which of the following statements is true about a quick termination connector
mr Goodwill [35]

A quick termination connector has two ends and contains fiber-optic connectors to bond with a ferrule.

<h3>What is a quick termination connector?</h3>

This refers to the fiber-optic connector that is used to reduce the installation time in the field for technical operators.

Hence, we can see that your question is incomplete so I gave you a general overview to help you get a better understanding of the concept.

Read more about fiber-optic connectors here:

brainly.com/question/14329759

#SPJ1

6 0
1 year ago
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