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s2008m [1.1K]
3 years ago
6

Question 7 of 10

SAT
1 answer:
Alika [10]3 years ago
5 0
The Answer is: C. 1.0
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What are the consequences of a strict interpretation of the term commerce
prohojiy [21]

What kinda question is this

5 0
3 years ago
Which statements accurately describe the persian wars.
Leokris [45]

Answer:

Greek drama addressed the complexity of universal human struggles. Comedies made fun of political corruption, intellectual developments

Explanation:

4 0
2 years ago
A single-platter disk has rotation speed 7200 rpm, number of tracks on one side of platter is 30,000, number of sectors per trac
nexus9112 [7]

Answer:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector. Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track O. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head

to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred

tracks traversed. So the seek time for 29,999 tracks traversed is

14999.5/100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So 1/120 = 0.00833 sec

= 0.00833 * 100

= 0.833 ms

So there is 1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333/2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d) Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

4 0
2 years ago
A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much work was done?
Allushta [10]

Answer:

45 J

Explanation:

Work done = force × displacement

(<em>displacement</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>shortest</em><em> </em><em>distance</em><em> </em><em>the</em><em> </em><em>object</em><em> </em><em>travels</em><em> </em><em>when</em><em> </em><em>a</em><em> </em><em>force</em><em> </em><em>is</em><em> </em><em>applied</em><em> </em><em>on</em><em> </em><em>it</em><em>)</em>

W = 15 × 3

= 45 J

[Note: While using the formulae, all quantities must be in their SI units.]

7 0
2 years ago
Which statement best explains the meaning added by the allusion in this excerpt? alluding to the ancient festival of lupercal de
Sergio [31]

The statement that best explains the meaning that is added by the allusion is

  • Lupercal alludes to an important patriotic festival, and celebrating Caesar on Lupercal indicates his high position in Rome.

<h3>What festival was the lupercal?</h3>

This was a festival that was celebrated in the ancient city of Rome in order to purify the city.

The excerpt from which this question was lifted stated that the Marullus made reference to the Lupercal and this makes him afraid.

Flavius tries to tell him that there was no need for fear given that the festival was important.

Read more on Shakespeare here:

brainly.com/question/12543737

7 0
2 years ago
Read 2 more answers
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