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3 years ago

Please help me find this one! I'm in highschool

Mathematics

1 answer:

kati45 [8]3 years ago

4 0

I think the answer is 60 but I’m not for sure

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Joshua and Isabella are having a snowball fight. Joshua has a snowball, shaped as a sphere, with a radius of 6 cm. Isabella also

denis-greek [22]

I think it might be 12

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3 years ago

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Let f(x)=−1/4(x+4)^2−8 . What is the average rate of change for the quadratic function from x=−2 to x = 2? Enter your answer in

kiruha [24]

Answer:

Average rate of change of function is -2.

Step-by-step explanation:

Given $f(x)=\frac{-1}{4}(x+4)^2-8$ .

we have to find the average rate of change for the quadratic function from x=−2 to x = 2.

$f(-2)=\frac{-1}{4}(-2+4)^2-8=\frac{-1}{4}(4)-8=-9$

$f(2)=\frac{-1}{4}(2+4)^2-8=\frac{-1}{4}(36)-8=-17$

The average rate of change of the function f(x) on interval [-2,2] is

$\frac{f(b)-f(a)}{b-a}=\frac{f(2)-f(-2)}{2-(-2)}=\frac{-17-(-9)}{4}=\frac{-8}{4}=-2$

3 0

3 years ago

In the accompanying diagram, the legs of right triangle ABC are 5 and 12 and the hypotenuse is 13. What is the value of cos A? A

disa [49]

$\cos A=\frac{5}{13}$

answer: C

7 0

1 year ago

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g. How many of each weight is needed?

Delicious77 [7]

The required number of weights used in chemical balance to weigh 237g is 4,1,1,7 respectively.

What is mathematical expression?

A mathematical expression expression in mathematical is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Here, it is given that :

A chemical balance needs to weigh 237g using weights of 50g, 20g, 10g and 1g.

Now, let us find the number of weights for each weight type :

For 50g weight the maximum number of weights needed will be 4 that is :

50g x 4 = 200g

Now, for 20g weight the maximum number of weights needed will be 1 that is :

20g x 1 = 20g

Now, for 10g weight the maximum number of weights needed will be 1 that is :

10g x 1 = 10g

Now, for 1g weight the maximum number of weights needed will be 7 that is :

1g x 7 = 7g

Adding all the weights we get :

200g + 20g + 10g + 7g = 237g;

which is the required weight and the number of weights used is 4,1,1,7 respectively.