Answer:
24.4 sq. ft.
Step-by-step explanation:
Area of a right square pyramid is:
A = a^2 + 2(a)*square root of ((a^2/4) + b^2)
A = 4 + 4 (square root of ((4/4) + 25) = 4 + 4* square root of 26
A = 4 + 4*5.099
A = 4 + 20.396
A = 24.396 sq ft.
Inscribed Quadrilateral Theorem says that quadrilateral can be inscribed in a circle if and only if the opposite angles are supplementary.
That means
∠C+∠A=180⁰
∠B+∠D=180⁰
So, ∠C+∠A=180⁰ ---->84 + x = 180 ------> x=180-84=96⁰.
Answer: x=96⁰.
Answer:
The area of the circle is 113.0 ft²
Step-by-step explanation:
To solve this problem we need to use the area formula of a circle:
a = area
r = radius = 6ft
π = 3.14
a = π * r²
we replace with the known values
a = π * (6ft)²
a = π * 36ft²
a = 113.04ft²
The area of the circle is 113.04ft²
round to the nearest tenth
a = 113.04ft² = 113.0 ft²
The answer is 12 5/18 hope it helps
I used a graphing calculator for this.
The solution my calculator got was:
(-2.625, 0.688) My calculator is very accurate, I don't think the test expects it to be like that.
Let's find the closest coordinates.
"B" is the closest.
I hope this helps!
~kaikers
