The given equation of the line is,
y = x/2 + 6
The given equation is slope-intercept form where the general form is,
y = mx + b
where m is the slope and the y-intercept is b.
From the equation it can be identified that m = 1/2 and b = 6. The slope of the line that is parallel to the given equation is also 1/2. Thus, using the slope-point form of the forming the equation,
y - y₁ = m(x - x₁)
Substituting the known values,
y - (-2) = (1/2)(x - 0)
y + 2 = x/2
Transposing the constant to the right-hand side of the equation the equation becomes,
y = x/2 - 2
<em>ANSWER: y = x/2 - 2</em>
Answer:
b)
{t | –3 < t ≤ 5}
Step-by-step explanation:
–4 < 3t + 5 ≤ 20
⇔
-4 - 5 < 3t ≤ 15
⇔
-9 < 3t ≤ 15
⇔
-3 < t ≤ 5
The answer to your question would be y2 +5y.