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monitta
3 years ago
6

Explain what it means for a solution of an equation to be extraneous.

Mathematics
1 answer:
HACTEHA [7]3 years ago
4 0

Answer:

Extraneous Solutions An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation. Example 1: Solve for x, 1 x − 2 + 1 x + 2 = 4 (x − 2) (x + 2).

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Find the value of x in the picture
MatroZZZ [7]

Answer:

100º

Step-by-step explanation:

It is across from the angle labeled 100º, therefore, it is also 100º.

Hope this helps! Have a great day!

8 0
3 years ago
Read 2 more answers
All parallelograms are ?
valentinak56 [21]

Answer:

<h2>Congruent</h2>

it just is

5 0
4 years ago
Are the equations 3x=-9 and 4x=-12 equivilant? explain.
patriot [66]
Yes because if you simplify them, both are going to give x= -3
5 0
4 years ago
How do you solve this problem? population proportion is to be estimated from a sample of 400 with a sample proportion of 0.1. Ap
Ivan

Answer:

(0.0706, 0.1294)

Step-by-step explanation:

Confidence interval of a proportion is:

CI = p ± CV × SE

where p is the proportion,

CV is the critical value (z score or t score),

and SE is the standard error.

The sample is large enough to estimate as normal.  For 95% confidence level, CV = z = 1.96.

Standard error for a proportion is:

SE = √(pq/n)

SE = √(0.1 × 0.9 / 400)

SE = 0.015

The confidence interval is:

CI = 0.1 ± (1.96)(0.015)

CI = (0.0706, 0.1294)

Round as needed.

6 0
3 years ago
What do i have to look up to learn how to do this kind of trig. I went through kahn academy for trig but this stuff never came u
mariarad [96]

Answer:

  (e) √(x² -1)

Step-by-step explanation:

You can look up the Pythagorean theorem, and SOH CAH TOA.

__

<h3>Pythagorean theorem</h3>

This tells you the relations between the sides of a right triangle. For the purpose of finding tan(θ), you need to know the length of the side that is not marked on the diagram. It is found using the Pythagorean theorem.

The sum of squares of the legs is equal to the square of the hypotenuse. If we call the unknown leg "o", then ...

  1² +o² = x² . . . . . the Pythagorean relation

  o² = x² -1 . . . . . . subtract 1

  o = √(x² -1) . . . . take the square root

__

<h3>SOH CAH TOA</h3>

This mnemonic reminds you of the relationship between trig functions and side lengths of a right triangle.

  • Sin = Opposite/Hypotenuse
  • Cos = Adjacent/Hypotenuse
  • Tan = Opposite/Adjacent

This tells you that tan(θ) is the ratio of the side opposite θ to the side adjacent:

  tan(θ) = o/1 = o

From the previous section, o = √(x²-1), so ...

  tan(θ) = √(x² -1) . . . . . . . matches choice (e)

_____

<em>Additional comment</em>

Another way to think about this is in terms of the trig identities you have learned:

  sec(θ) = 1/cos(θ) = 1/(1/x) = x

  sec²(θ) = tan²(θ) +1   ⇒   tan(θ) = √(sec²(θ) -1) = √(x² -1)

7 0
2 years ago
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